Coordination Chemistry and d electron numbers

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SUMMARY

The discussion centers on predicting the number of unpaired electrons in the coordination complex [Cr(H2O)6]3+. The consensus is that chromium (Cr) in this complex is in a +3 oxidation state, resulting in a d3 electron configuration. This is derived from the fact that Cr has an atomic number of 24, leading to a d4 configuration in its neutral state. Upon losing three electrons due to the +3 charge, the configuration becomes d3, which is crucial for determining the number of unpaired electrons in octahedral complexes.

PREREQUISITES
  • Understanding of coordination chemistry
  • Knowledge of electron configurations and oxidation states
  • Familiarity with octahedral crystal field theory
  • Basic principles of molecular orbital theory
NEXT STEPS
  • Study the crystal field splitting in octahedral complexes
  • Learn about the impact of oxidation states on electron configurations
  • Explore the concept of unpaired electrons and their significance in magnetism
  • Investigate other transition metal complexes and their electron configurations
USEFUL FOR

Chemistry students, educators, and researchers interested in coordination chemistry and the behavior of transition metals in various oxidation states.

ReidMerrill
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Homework Statement


Predict the number of unpaired electrons

[Cr(H2O)6]3+

Homework Equations

The Attempt at a Solution


I under stand how to fill out the MO with the eg and t2g and all but I'm confused about determining the number of electrons.
The answers state this is an octahedral d3 but I don't know why it is d3
Cr is the 4th element in the d block so it should be d4 but since it has a charge of +3 / is missing 3 electrons it should be d1 but neither of these are correct.
 
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Cr has no s electrons?
 
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