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Corollary from Cauchy's integral formula
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[QUOTE="mahler1, post: 4774070, member: 483655"] Oh, what a fool of me, I should have put ##h[\dfrac{1}{(ζ−z)^2}][\dfrac{n}{(ζ−z)^{n−1}}]## but, as you've said, then ##h## will cancel with ##\dfrac{1}{h}##. Thanks for your answer, now I see why it converges to that expression. [/QUOTE]
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Corollary from Cauchy's integral formula
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