Correct vector diagram of forces

AI Thread Summary
The discussion centers on understanding the correct vector diagram of forces acting on a hinge in static equilibrium. The force on the hinge has both horizontal and vertical components, with the horizontal component directed to the right to balance tension. The vertical component can be either upward or downward, but clarification is sought on why it should be downward in this scenario. The importance of considering resultant torque at different pivot points is emphasized for accurate analysis. The conversation also touches on the implications of replacing the hinge with a slider, which would require an external downward force to maintain equilibrium.
songoku
Messages
2,470
Reaction score
386
Homework Statement
Please see below
Relevant Equations
Equilibrium
1662253423830.png
The answer is (B) but I don't understand why (C) is wrong. The force acting on the hinge has two components, horizontal and vertical. The horizontal component must be to the right to balance the horizontal component of tension but the vertical component can be either upwards or downwards. Wow to know the correct direction is downwards?

Thanks
 
Physics news on Phys.org
Hint: What are the conditions for static equilibrium of such an object?
 
robphy said:
Hint: What are the conditions for static equilibrium of such an object?
I get the hint. I need to consider resultant torque at different pivot.

Thank you very much for the help robphy
 
If you replace that hinge with a slider, which is free to move up and down that wall, an external down force would be needed to counteract the moment that W induces about the point of connection of the cable to the trapdoor.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...

Similar threads

Back
Top