Correlation energy between two electrons

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SUMMARY

The discussion centers on calculating the expectation value of the correlation energy between two electrons repelling each other through classical Coulomb interaction, represented by a complex 6-dimensional integral. The integral is expressed as \left\langle\frac{1}{|\vec{r}_1 - \vec{r}_2|}\right\rangle =\int_{-\infty}^{\infty}d\vec{r}_1d\vec{r}_2e^{-2\alpha(r_1 + r_2)}\frac{1}{|\vec{r_1}-\vec{r_2}|}, with the expected result being \frac{5\pi^2}{16^2}. Participants suggest using the law of cosines to simplify the denominator and recommend expanding the integral using spherical coordinates. However, complications arise in relating the angular differentials to the cosine terms, indicating a need for further exploration of integral transformation techniques.

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Hello. I need to find the expectational value of the correlation energy between two electrons which repel each other via the classical Coulomb interaction. This is given by the 6-dimensional integral:
\left\langle\frac{1}{|\vec{r}_1 - \vec{r}_2|}\right\rangle =\int_{-\infty}^{\infty}d\vec{r}_1d\vec{r}_2e^{-2\alpha(r_1 + r_2)}\frac{1}{|\vec{r_1}-\vec{r_2}|}
r_i = |\vec{r}_i|, \quad \vec{r}_i = x_i \hat{i} + y_i\hat{j} + z_i\hat{k}, \quad i = 1,2
I know that the answer is \frac{5\pi^2}{16^2}, however I can't seem to find a method for solving this type of integrals in any of my books. I have tried to use spherical coordinates, which seemed logical due to the answer having a factor of \pi^2, but with no luck. And it is a couple of years since I've been solving integrals like this one, so a nudge in the right direction is greatly appriciated.

(It is a bonus question in one of the projects in the course: computational physics)
 
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Hello.
Try using the law of cosines to expand the denominator and do one integral at a time.
 
Thank you for your reply.
This is one of the things which I've been trying to do. However I end up with a result which is a very complicated integral. Expanding the difference of the length of the two vectors gives:
|\vec{r}_1 - \vec{r}_2| = \sqrt{r_1^2 + r_2^2 - 2r_1 r_2 \cos\beta} Where \cos\beta = \cos\theta_1\cos\theta_2 + \sin\theta_1\sin\theta_2 \cos(\phi_1 - \phi_2)
I then need to expand d\vec{r}_1 and d\vec{r}_2, which can be done in spherical coordinates as: d\vec{r}_i = r_i^2 \sin\theta_i dr_id\theta_id\phi_i, i = 1,2 or d\vec{r}_1d\vec{r}_2 = r_1^2r_2^2dr_1dr_2d\cos\theta_1d\cos\theta_2d\phi_1d\phi_2
This is were I end up with the integral
\left\langle\frac{1}{|\vec{r}_1 - \vec{r}_2|}\right\rangle = \int_{-\infty}^{\infty}e^{-2\alpha(r_1 + r_2)} \frac{r_1^2r_2^2dr_1dr_2d\cos\theta_1d\cos\theta_2d\phi_1d\phi_2}{\sqrt{r_1^2 + r_2^2 - 2r_1 r_2\cos\beta}}
I can't seem to find a usefull relation between d\cos\theta_1d\cos\theta_2d\phi_1d\phi_2 and d\beta or \cos\beta. Any ideas on how I can proceed?
Thanks in advance.
 

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