What Are the Cosets in Q/Z(Q)?

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SUMMARY

The discussion focuses on finding the cosets in the quaternion group Q with respect to its center Z(Q). It is established that Z(Q) is the center of Q and is normal in Q. The cosets are derived from the elements of Q, with representatives identified as {1, -1}, {i, -i}, {j, -j}, and {k, -k}. The operation involved is addition, confirming that Q is commutative and Z(Q) equals Q.

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  • Knowledge of group theory concepts, specifically normal subgroups
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Homework Statement


Find the cosets in Q/Z(Q)


Homework Equations





The Attempt at a Solution



So Z(Q) is the centre of Q..
Then Z(Q) is normal in Q.

I don't get what the cosets would be without any given elements of Q or Z(Q)..
But I'm assuming since it is the centre of Q there is some trick?

Thanks.
 
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What is Q here? The quaternion group? I will assume it is.

What is the center of Q? Does i commute with every element? does j? does k? does -1? etc.? Once you have determined the center you should be able to find representatives for every coset in Q/Z(Q).
 
Hmm, is the operation simply addition? If so, Q is commutative, and Z(Q)=Q.
 
I get:
{1,-1} = Z(Q)= Z(Q)(-1)
{i, -i} = Z(Q)i = Z(Q)(-i)
{j, -j} = Z(Q)j = Z(Q)(-j)
{k, -k} = Z(Q)k = Z(Q)(-k)

is this correct?
 
Yes, this is correct. Sorry for the first answer, I thought Q ment rationals...
 

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