NoDoubt said:
Thanks, I got my answer, I was talking about the OP's scenario. (Sphere with a hole)
I know there is no perfect sphere ever made to trap the light.
Let us say reflective index of a closed sphere is 99%. only 1% of the light is being absorbed,
That's actually a very low reflective index, even if only 1% of photons are absorbed each time they hit the sides, they are bouncing back and forth very frequently since they move at light speed (unless you're talking about a sphere light-years across or something). The
book I linked to earlier was discussing mirrors with a reflectivity of 99.99%...
NoDoubt said:
Now if the light source inside the sphere suddenly increases it's brightness to extreame level. what will happen? Will 1% impurity in the sphere be enough to absorb all the extra photons?
Total number of photons shouldn't matter, if the reflectivity of the sphere is 99% then each time the photons bounce back and forth between walls, 1% of the remaining photons should be absorbed.
NoDoubt said:
or will the sphere explode? like a bottle with a small hole in it, and water rushing into it with high preasure.
Light pressure from the kind of light sources we have on Earth is extremely weak. And even if you could withstand the intensity of light that would be seen by someone right next to the surface of the Sun, the pressure on a human-sized object would still be pretty weak!* I don't know what you mean when you say the light source increases to an "extreme level" but unless the source is absurdly powerful (or the material making up the sphere absurdly thin) it's not going to be enough to break it apart.
*According to the equation
here the intensity of sunlight as a function of radius R is given by 3.2x10^25(1/R^2) (watts/m^2), and the radius at the surface is about 6.955 * 10^8 meters, so at the surface of the Sun the intensity would be about 6.6 * 10^7 watts/square meter, or 6.6*10^7 joules of energy per second on each square meter, with 1 joule = 1 kg*m^2/s^2. This is a lot of energy, but for photons the
momentum is given by E/c with c=299792458 m/s, so this only works out to about 0.22 kg * m/s of momentum change per second for each square meter of surface area. So if you were exposed to light this intense in deep space with no gravity (so the light was the only force on you), then if your body has 0.7 m^2 of surface area exposed to the light source and absorbs all the photons hitting it, and you weigh 70 kg, then you will only be accelerated at a rate of 0.22*0.7/70=0.0022 m/s per second, so for example after 60 seconds your speed has only changed by 0.132 m/s, a change of a little under 0.3 miles/hour (if you instead reflected all the incoming photons, this would only double the radiation pressure according to
this page).