Coulomb's law and related problem

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Homework Help Overview

The discussion revolves around a problem involving Coulomb's law and the interaction between two point charges. The original poster presents a scenario where the sum of two charges is 6µC, and they attract each other with a force of 0.9 N when separated by 40 cm in a vacuum. The goal is to determine the individual charges.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to set up equations based on the sum and difference of the charges, applying Coulomb's law to find the individual charges. Some participants suggest clarifying the signs of the charges and the implications of attraction on their values.

Discussion Status

Participants are actively engaging with the problem, questioning the assumptions made about the signs of the charges. There is a recognition that one charge must be negative for attraction to occur, and some guidance has been offered regarding the correct formulation of the equations.

Contextual Notes

There is a noted confusion regarding the interpretation of the equations set up by the original poster, particularly in distinguishing between the sum and difference of the charges. This highlights the importance of correctly framing the relationships between the charges in the context of the problem.

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Homework Statement



The sum of two point charges is 6µC. They attract each other with a force of 0.9 N, when kept 40 cm apart in vacuum. Calculate the charges.

Homework Equations





The Attempt at a Solution


q1+(-q2) = 6x10-6
q1-q2=6x10-6...I
q1=6x10-6+q2
According to Coulomb's law
F=q1q2/4πε0r2
.9=(6x10-6+q2)q2/4πε0(.4)2
.9=(6x10-6q2+q22)x9x109/.16
.144/9x109=6x10-6q2+q22
144x10-3x10-9/9=6x10-6q2+q22
q22+6x10-6q2-16x10-12=0
(q2+8x10-6)(q2-6x10-6)=0
q2=-8µC or q2=6µC
The answers given in the book are q1 = 8micro Coulomb and q2= -2 microcoulomb
I don't understand how to get this answer because when q2 = 8 microcoulomb and substituting in equation I , i get q1+8micro coulomb =6 micro coulomb so q1 should be -2 micro coulomb
Did i miss anything in the steps? Members, please help me .



 
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logearav said:

The Attempt at a Solution


q1+(-q2) = 6x10-6
q1-q2=6x10-6...I
q1=6x10-6+q2
Since you're assuming that q1 is positive and that q2 is negative, you don't need to wedge in that extra minus sign. Just write q1 + q2 = 6x10-6C.
According to Coulomb's law
F=q1q2/4πε0r2
.9=(6x10-6+q2)q2/4πε0(.4)2
Since one of the charges is negative the product q1*q2 will be negative, and thus the force should be negative also.

Let f = 0.9N, r = 0.40m, Q = 6μC, [itex]k = \frac{1}{4 \pi \epsilon_o}[/itex] Then

[itex]Q = q_1 + q_2[/itex] so that [itex]q_2 = Q - q_1[/itex]

[itex]f = -k \frac{q_1 q_2}{r^2} = -k \frac{q_1 (Q - q_1)}{r^2}[/itex]
 
it has been mentioned that two charges attract each other that's why i took q2 as negative. is my assumption wrong, sir?
 
logearav said:
it has been mentioned that two charges attract each other that's why i took q2 as negative. is my assumption wrong, sir?

No, the assumption is fine. Oppositely signed charges attract. Either q1 or q2 must be negative (but not both!).
 
Thanks a lot for the reply, sir. Then why i didn't get the correct answer when i framed the equation q1-q2= 6 micro coulomb, taking q1 as positive and q2 is negative. I got the correct answer when i proceeded as suggested by you. But what's wrong with my assumption?
 
logearav said:
Thanks a lot for the reply, sir. Then why i didn't get the correct answer when i framed the equation q1-q2= 6 micro coulomb, taking q1 as positive and q2 is negative. I got the correct answer when i proceeded as suggested by you. But what's wrong with my assumption?

q1 - q2 is the difference between the charges, not the sum of the charges.
 
I got it sir. Thanks a lot for patiently helping me.
 

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