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logearav
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Homework Statement
The sum of two point charges is 6µC. They attract each other with a force of 0.9 N, when kept 40 cm apart in vacuum. Calculate the charges.
Homework Equations
The Attempt at a Solution
q1+(-q2) = 6x10-6
q1-q2=6x10-6...I
q1=6x10-6+q2
According to Coulomb's law
F=q1q2/4πε0r2
.9=(6x10-6+q2)q2/4πε0(.4)2
.9=(6x10-6q2+q22)x9x109/.16
.144/9x109=6x10-6q2+q22
144x10-3x10-9/9=6x10-6q2+q22
q22+6x10-6q2-16x10-12=0
(q2+8x10-6)(q2-6x10-6)=0
q2=-8µC or q2=6µC
The answers given in the book are q1 = 8micro Coulomb and q2= -2 microcoulomb
I don't understand how to get this answer because when q2 = 8 microcoulomb and substituting in equation I , i get q1+8micro coulomb =6 micro coulomb so q1 should be -2 micro coulomb
Did i miss anything in the steps? Members, please help me .