Coulomb's Law: Calculating Force on Charged Particles

Click For Summary
SUMMARY

The discussion centers on applying Coulomb's Law to calculate the force between two charged particles. A force of 2.62 micro Newtons is exerted by particle A on particle B when they are 13.7 mm apart. As particle B moves to a distance of 17.7 mm, the correct application of Coulomb's Law, represented by the equation F = k q1 q2 / r^2, is necessary to determine the force exerted on particle A. The participants clarify that the value 2.62x10^-6 refers to the force, not the charge, indicating a misunderstanding in the initial setup.

PREREQUISITES
  • Coulomb's Law
  • Understanding of electric charge units (microcoulombs)
  • Vector force concepts
  • Basic algebra for manipulating equations
NEXT STEPS
  • Study the derivation and applications of Coulomb's Law
  • Learn how to calculate electric forces between multiple charges
  • Explore the concept of electric field strength and its relation to force
  • Investigate the principles of vector addition in force calculations
USEFUL FOR

Students studying physics, particularly those focusing on electromagnetism, as well as educators and anyone seeking to deepen their understanding of electric forces and Coulomb's Law applications.

tag16
Messages
95
Reaction score
0

Homework Statement


A charged particle A exerts a force of 2.62 micro Newtons to the right on charged particle B when the particles are 13.7 mm apart. Particle B moves straight away from A to make the distance between them 17.7 mm. What vector force does it exert on A?

using coulombs law: (8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?


Homework Equations



coulombs law: F=k q1q2/r^2

The Attempt at a Solution



(8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?
 
Physics news on Phys.org
tag16 said:

The Attempt at a Solution



(8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?

We don't know that the charges are 2.62 μC. The 2.62x10^-6 refers to the force, in Newtons.

You're correcting in using the equation,

F = k q1 q2 / r2

We don't know q1 or q2 here.
 

Similar threads

Replies
17
Views
3K
Replies
11
Views
2K
  • · Replies 8 ·
Replies
8
Views
4K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
6
Views
9K
Replies
1
Views
905
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
4
Views
2K