Coulomb's Law: Calculating Force on Charged Particles

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tag16
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Homework Statement


A charged particle A exerts a force of 2.62 micro Newtons to the right on charged particle B when the particles are 13.7 mm apart. Particle B moves straight away from A to make the distance between them 17.7 mm. What vector force does it exert on A?

using coulombs law: (8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?


Homework Equations



coulombs law: F=k q1q2/r^2

The Attempt at a Solution



(8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?
 
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tag16 said:

The Attempt at a Solution



(8.99x10^9)(2.62x10^-6)^2/(1.77x10^-2)^2

did I set this up right? if not what did I do wrong?

We don't know that the charges are 2.62 μC. The 2.62x10^-6 refers to the force, in Newtons.

You're correcting in using the equation,

F = k q1 q2 / r2

We don't know q1 or q2 here.