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Coulomb's Law - Calculating Net Force
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[QUOTE="Valentine, post: 4987085, member: 539937"] Micro! I feel very slow for not realizing it was micro That explains why it was 10^-6. Thank you! Also, I would have to use 0.7m^2 correct if it was from q1 to q3? I am trying the math and my numbers are not adding up. I am usually great with math but -- well I'll just show my work. I see! I had just crossed out mine but I think practicing it the way you're showing would be better for the future because I am sure it will come up and try to haunt me. I'll be ready for it though! F= K q1 q2 / r^2 =(9*10^9N*m^2/C^2) (70*10^-6C) (48x10^-6C) / 0.32^2 [B](0.35^2 Because it is from q1 to q2)[/B] = I ended up canceling out the C^2 and m^2 even though I understand haruspex's work and ended up with: [B] (9x10^-3N) (70) (48) / 0.35^2[/B] which is similar to haruspex's work but I left the N in the K area. =Multiplying the top I got [B]30.24N/0.35^2 [/B]=Finally I get [B]246.857 [/B] [B]I thought that it was my signs and double check and triple checked but I am not getting -1.4x10^2 or any numbers around 140.[/B] [B]________________[/B] [B]Okay I am seeing why. I am needing to come up with k q1 q3/r^2 THEN add them (I think)[/B] [B]________________[/B] [B]Yes! [/B]After doing the equation for q1 q3 I added up the two and got the answer! Thanks mfb and haruspex for your patience and time! I appreciate it now to do the other two parts of this problem! :D [/QUOTE]
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Coulomb's Law - Calculating Net Force
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