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## Homework Statement

An electron is fired at 4.0 e+6 m/s horizontally between the parallel plates as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 e+2 N/C. The separation of the plates is 2.0 cm.

a) Find the acceleration of the electron between the plates?

b) Find the horizontal distance traveled by the electron when it hits the plate?

c) Find the velocity as it strikes the plate?

## Homework Equations

a = qE/m

F = qE

d = x

_{i}+ y

_{i}∙t + ½ ∙ a ∙ t²

## The Attempt at a Solution

I've read the chapter a few times and I think this is right but I want to make sure I haven't made a careless error, Please and thank you for your help!

a) 7.0 e¹³ m/s²

b) This is the one I'm not sure about...

d = x

_{i}+ y

_{i}∙t + ½ ∙ a ∙ t²

d = 3.5 e¹³ m/s² ∙ t² + 0 + 0 = 2e-2 m

t = √ 2e

^{-2}/ 3.5 e¹³ = 2.4 eˉ⁸ s

d = 4.0 e⁶ m/s ∙ 2.4 eˉ⁸ s = 9.6 eˉ² m

c) ...and this...

v = y

_{i}+ a ∙ t

= 0 + 7.0 × 10¹³ m/s² ∙ 2.4 × 10ˉ⁸ s

= 1.7 × 10⁶ m/s

Thank you for your help :)