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Coulomb's Law, finding acceleration direction

  1. Mar 11, 2015 #1
    1. The problem statement, all variables and given/known data
    Two charges q1 = -7 and q2 = -2, both charges are fixed in place and the distance between them is 2m. Third negative charge q3 is moving along the vertical line that connects two charges.

    1) net force acting on q3 = 0; where is the charge located ?
    2) If charge q3 is released 0.5m above charge q1, in which direction is it going to accelerate ?

    2. Relevant equations
    F1 - F2 = 0
    x = position of q3
    q1/x2 = q2/(d-x)2


    3. The attempt at a solution
    After solving #1 the final formula that i came up with is x = d√q1/q2 / 1 + √q1/q2

    and #2 i have no clue how to solve this one...
     
  2. jcsd
  3. Mar 11, 2015 #2

    Bystander

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    Where is q2 relative to q1? Above? Below?
     
  4. Mar 11, 2015 #3
    q2 is above q1
     
  5. Mar 11, 2015 #4

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    Net force on q3 from the two fixed charges is then what?
     
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