(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two point charges are fixed on the y axis: a negative point charge q1 = -24 µC at y1 = +0.20 m and a positive point charge q2 at y2 = +0.37 m. A third point charge q = +9.0 µC is fixed at the origin. The net electrostatic force exerted on the charge q by the other two charges has a magnitude of 26 N and points in the +y direction. Determine the magnitude of q2.

2. Relevant equations

F = K(q1q2)/r^2

3. The attempt at a solution

First I found the magnitude of force between q and q1 and set up the equation for q1 and q2:

[(8.99*10^9)(9.0*10^-6)(2.4*10-5)]/(0.20^2) = 48.546N

[(8.99*10^9)(2.4*10^-5)(q2)]/(0.17^2) = F

Then I did my equation to find the force for the 2nd equation (-48.546 since it's an attractive force):

F - 48.546N = 26N

F = 74.546

Then solved for q2:

q2 = [(74.546)(0.17^2)]/[(8.99*10^9)(2.4*10^-5)] = 9.985*10^-6

WebAssign tells me I'm incorrect, and I can't tell where I've gone wrong...

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# Homework Help: Coulomb's Law magnitude problem

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