Coulombs Law Problem - Find the Force

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SUMMARY

The discussion focuses on solving a Coulomb's Law problem involving two charged objects, A and B, with charges of 2 µC and -2 µC, respectively, separated by 3 cm. The goal is to determine how many electrons must be transferred to create an attractive force of 68 N between them. The relevant formula used is F = k(q1 + ex)(q2 - ex) / r², where k is Coulomb's constant (8.99 x 10^9 N·m²/C²). The calculated charge needed for the force is 2.6 x 10^-6 C, leading to a requirement of approximately 1.63 x 10^13 electrons to achieve the desired force.

PREREQUISITES
  • Coulomb's Law (F = kq1q2/r²)
  • Understanding of electric charge (1.6 x 10^-19 C per electron)
  • Basic algebra for solving equations
  • Concept of electrostatic force and charge interaction
NEXT STEPS
  • Study the derivation of Coulomb's Law and its applications in electrostatics.
  • Learn how to manipulate equations involving multiple variables in physics problems.
  • Explore the concept of charge conservation in electrostatic interactions.
  • Practice solving complex Coulomb's Law problems with varying charge configurations.
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Students studying physics, particularly those focusing on electrostatics, as well as educators looking for examples of Coulomb's Law applications in problem-solving.

KatieD
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Coulombs Law Problem -- Find the Force

Homework Statement


Two small objects, A and B, are fixed in place and separated by 3 cm in vacuum. Object A has a charge of 2 uC and object B has a change of -2 uC. How many electrons must be removed from A and put onto B to make the electrostatic force that acts on each object an attractive force whose magnitude is 68 N?

We know an electrons charge is 1.60*10^-19 C

Homework Equations


F=kq1q2/r^2 (coulombs law)

The Attempt at a Solution



I tried to solve for q (the charge). Since they are both the same I took the square root. Then I divided by the charge of e-. I am out of ideas :(

I can do simple coulombs law problems in this chapter, but the harder ones like this stump me. :((Thanks,
Katie
 
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KatieD said:
I tried to solve for q (the charge). Since they are both the same I took the square root Then I divided by the charge of e-.

So after doing this, what is the quantity that you have arrived at? What is q/e?
 


F = K*Q^2/r^2
68 = (8.99 * 10^9 N * m^2/C^2)(q^2)/(3*10^-2)^2
q=2.6*10^-6 C
e=1.6*10^-19
(2.6*10^-6C)/(1.6*10^-19)=1.63*10^13

the answer in the back is 3.8*10^12
 


I'm not asking for the number.

I'm saying: if q is the charge, and e is the charge per electron, what does the quantity q/e mean? How does that relate back to what the question wants?
 


q/e is going to be the number of e. But I guess that would be the number of e- for that charge. So they ask for the e- to change the charge. Would I then find the difference by subtracting from 2 and then dividing by e-?
 


The question wants x electrons per object.
You just calculated the no. of electrons you need
From the question you can find out how many electrons you had at the start.

Hopefully its obvious enough now?
 


okay got ya, I just need to take it into consideration with the initial formula
instead of solving for just q I am solving for q+ex
 


Ok, I can't seem to get the right answer and I don't know where I'm going wrong.

I set the equation up as

F = k(q1 + ex)(q2 - ex) / r^2

where q1 is the positive charge and q2 is the negative charge.

So this works out to

68 = (8.99*10^9)(2*10^-6 + x*1.6*10^-19)(-2*10^-6 - x*1.6*10^-19) / (3*10^-2)^2

but this doesn't lead to the right answer. Where is my set up going wrong?
 


It does, I've checked. Calculator error somewhere?
 

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