Coulomb's Law, Rearranging Equation.

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    Coulomb's law Law
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To find the distance between two electrostatic point charges of +60 microCoulombs and +50 microCoulombs exerting a force of 175 N, the equation Fe = Kc (q1*q2/r^2) is used. Rearranging the equation leads to r^2 = Kc*q1*q2/Fe. Taking the square root of both sides gives the final formula R = √(Kc*q1*q2/Fe). This approach confirms that solving for r involves straightforward algebraic manipulation. The discussion highlights the simplicity of the rearrangement process in applying Coulomb's Law.
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Homework Statement



Two electrostatic point charges of +60 microCoulombs and +50 microCoulombs exert a repulsive force on each other of 175 N. What is the distance between the two charges?


Homework Equations


Fe=Kc (q1*q2/r^2)


The Attempt at a Solution


I know I need to rearrange the equation, to get r^2 over to the other side of the equation. Do I have to square root both sides to figure this out?

Fe=Kc (q1*q2/r^2)
*r^2 * r^2

Fe*r^2 = Kc (q1*q2)
/Fe /Fe

R^2=Kc*q1*q2/Fe
 
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Welcome to PF!

Hi Syncert! Welcome to PF! :smile:

(try using the X2 and X2 icons just above the Reply box :wink:)
Syncert said:
I know I need to rearrange the equation, to get r^2 over to the other side of the equation. Do I have to square root both sides to figure this out?

Fe=Kc (q1*q2/r^2)
*r^2 * r^2

Fe*r^2 = Kc (q1*q2)
/Fe /Fe

R^2=Kc*q1*q2/Fe

Yes, that's fine …

R = √(Kc*q1*q2/Fe) :smile:
 
Wow it was really that simple...thank you. =]
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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