The problem involves calculating the magnitude of the electric force between two protons that are 2.5 femtometers apart, utilizing Coulomb's law.
Some participants have provided clarifications regarding the charge of protons and electrons, noting their equal magnitudes but opposite signs. There is ongoing exploration of the implications of these charges in the context of the problem.
Participants express confusion regarding the charge values and their application in the formula, indicating a need for further clarification on the relationship between protons and electrons.
You have two charges:Sox281212 said:I got the answer but I don't understand why I am able to use e= 1.6 x 10-19 as q1 and q2? could someone explain? thanks
Sox281212 said:Wait, I'm confused.. isn't 1.6 x 10^-19 the charge of an electron?! Oh wait, is it because charge of electron = charge of proton if its neutral?
Charge of electron = -charge of proton. The thing that's neutral is the atom, comprising electrons, equal number of protons yielding the "neutrality", plus possibly neutrons which have no charge. ( The exception is ions which do have a net charge. Example: add salt to water, you get mostly sodium and chlorine ions).Sox281212 said:Wait, I'm confused.. isn't 1.6 x 10^-19 the charge of an electron?! Oh wait, is it because charge of electron = charge of proton if its neutral?