counterexample so that (ab)^i=a^ib^i for two consecutive integers for any a and b in a group G does not imply that G is abelian.(adsbygoogle = window.adsbygoogle || []).push({});

this is a problem in herstein and i'm struggling to find an example. The previous problem to show that if (ab)^i=a^ib^i for 3 consecutive integers then G is abelian is a starred problem but seems to be easier.

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# Counterexample so that (ab)^i=a^ib^i for two consecutive integers

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