Counting Combinations: How to Divide 4 Articles Between 2 People | Homework Help

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Homework Help Overview

The problem involves determining the number of ways to divide 4 articles between 2 people, ensuring that each person receives at least one article. The context suggests a combinatorial approach to the distribution of distinct items.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss different methods for counting combinations, including listing possibilities and using combinations notation. Some question the independence of the articles and clarify the nature of the items being divided.

Discussion Status

The discussion has seen various attempts to calculate the total number of ways to distribute the articles, with some participants expressing uncertainty about their initial calculations. There is a mix of strategies being explored, and while one participant claims to have resolved their confusion, no explicit consensus has been reached on the final count.

Contextual Notes

Participants note that the articles may not be identical and that the distribution must adhere to the condition that each person receives at least one article. There is also mention of using combinations notation as a potential simplification in counting methods.

lionely
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Homework Statement



In how many ways can 4 articles be divided between 2 people when each person must receive at least one article?

Homework Equations





The Attempt at a Solution



I tried it like this

Person 1 could have ( 3,2 or 1 paper(s) )

Person 2 the same so

total # ways = 6 + 6 = 12

But this is wrong.
 
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The number of articles each person has is not independent.
It is not clear that the articles are identical - suspect not.

Label the articles 1,2,3,4
(note: an "article" need not be a paper - it can be any object, like "an article of clothing".)

Label people as A and B (Alice and Bob, say).

Now list the different ways Alice and Bob can have some stuff.
Start by giving Alice one article and Bob the rest.
Then give Alice two articles, then three.
 
So like A-1, B-3 = 3 ways
A-2, B-2 = 4 ways

A-3,B-1 = 3 ways
So total # = 10 ways?
 
Nevermind I got it thanks.
 
Well done: what did you come up with?
(JIC someone else gets stuck - then they benefit from your efforts)
 
I had the first possibility ( 4C1 x 3C3)
2nd (4C2 x 2C2)
3rd (4C1 x 3C3)

Then I added them up to get the total number of ways of carrying out the selections. I got 14.
 
Cool - what made you suddenly switch to combinations notation?

The question amounts to asking the number of ways Alice can pick at most 3 articles out of 4 when the order doesn't matter.

That's (4x3x2)/(3x2)+(4x3)/(2)+4=4+6+4=14.

There's so few you can just list them.
 
Usually when I can't count it out lol I try Combinations, some times it just seems easier with combinations.
 

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