Coupled pendulum-spring system

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SUMMARY

The discussion focuses on the mathematical representation of the separation vector in a coupled pendulum-spring system. The separation vector is defined as ##\vec x = l(\theta_2 - \theta_1) \hat{k}##, where ##\hat{k}## is the unit vector along the spring. Participants clarify that for small angles, the unit vectors ##\hat{x_2}## and ##\hat{x_1}## can be approximated as ##\hat{k}##, simplifying the analysis. The confusion arises from understanding the relationship between arc lengths and displacements in this context.

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Homework Statement
Please see below. I have a doubt about the solution of the problem.
Relevant Equations
Arc length = ##R\theta##
The problem and solution are,
1712980472532.png

1712980490956.png

1712980508579.png

However, I am confused how the separation vector between the two masses is

##\vec x = x \hat{k} = x_2 \hat{x_2} - x_1 \hat{x_1}= l\theta_2 \hat{x_2} - l\theta_1 \hat{x_1 } = l(\theta_2 - \theta_1) \hat{k}##. where I define the unit vector from mass 2 to mass 1 as ##\hat{k}## along the spring. Does someone please know of a algebraic or geometric proof for this?

Thanks a lot!
 
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ChiralSuperfields said:
Homework Statement: Please see below. I have a doubt about the solution of the problem.
Relevant Equations: Arc length = ##R\theta##

The problem and solution are,
View attachment 343276
View attachment 343277
View attachment 343278
However, I am confused how the separation vector between the two masses is

##\vec x = x \hat{k} = x_2 \hat{x_2} - x_1 \hat{x_1}= l\theta_2 \hat{x_2} - l\theta_1 \hat{x_1 } = l(\theta_2 - \theta_1) \hat{k}##. where I define the unit vector from mass 2 to mass 1 as ##\hat{k}## along the spring. Does someone please know of a algebraic or geometric proof for this?

Thanks a lot!
Which particular step worries you?
It seems a bit verbose to me. Why introduce ##\hat{x_2} ## and ## \hat{x_1}##? Aren’t they obviously ##\hat k## for small perturbations (compared to the length of the spring)?
 
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haruspex said:
Which particular step worries you?
It seems a bit verbose to me. Why introduce ##\hat{x_2} ## and ## \hat{x_1}##? Aren’t they obviously ##\hat k## for small perturbations (compared to the length of the spring)?
Thank you for your reply @haruspex!

Sorry are you saying that ##\hat{x_2} = \hat{x_1} = \hat{k}## for small ##\theta##? My confusion is how the spring displacement from equilibrium position is ##l\theta_2 - l\theta_1 = l\theta_1 - l\theta_2## since the displacement is squared. I am confused when I try to imagine subtracting two arc lengths from each other.

Thanks!
 
ChiralSuperfields said:
My confusion is how the spring displacement from equilibrium position is ##l\theta_2 - l\theta_1 = l\theta_1 - l\theta_2## since the displacement is squared. I am confused when I try to imagine subtracting two arc lengths from each other.

Thanks!
For small perturbations, the arc length is near enough the same as the displacement in the initial tangential direction, i.e. the ##\hat k## direction.
Since it is squared, it does not matter which way around you do the subtraction.
 
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