Covalent Bonding: O2 vs S8 - Understand the Logic

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SUMMARY

The discussion centers on the molecular structures of O2 and S8, highlighting that O2 forms a double bond to achieve a stable octet, while S8 exists as a cyclic molecule due to its lower energy state under specific conditions. The participants emphasize that the stability of S8 is not easily explained by simple rules, as it results from complex interactions and electron correlation effects. Quantum chemistry is suggested as a necessary field of study to understand these phenomena better.

PREREQUISITES
  • Understanding of molecular bonding concepts, specifically covalent bonding.
  • Familiarity with the octet rule and its exceptions.
  • Basic knowledge of quantum chemistry principles.
  • Awareness of electron correlation and its impact on molecular stability.
NEXT STEPS
  • Study the principles of quantum chemistry to grasp electron interactions.
  • Research the concept of electron correlation in molecular structures.
  • Explore the stability of different allotropes of sulfur, including S4, S6, and S8.
  • Learn about molecular orbital theory and its application to covalent bonding.
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Chemistry students, educators, and researchers interested in molecular bonding, particularly those exploring the complexities of covalent bonds and molecular stability in non-ideal systems.

dnorric
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Ok I understand that O2 wants to have a stable number of electrons for its period which is 8 and so it shares two pairs of electrons. But what about S8. I thought it would form S2. Why is it forming S8, what is the logic.
Cheers
Damian
 
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I am afraid there is no simple logic behind. For some reasons S8 has the lowest energy in a given circumstances. Quite often that's just the way it is and it is not possible to give a systematic explanation other than "if you calculate the energy of different molecules, there is a minimum here".
 
This is why chemistry drives me crazy. There are so many exceptions to the rule, it hardly seems a science in comparison to physics. Thanks heaps for your help though

Borek said:
I am afraid there is no simple logic behind. For some reasons S8 has the lowest energy in a given circumstances. Quite often that's just the way it is and it is not possible to give a systematic explanation other than "if you calculate the energy of different molecules, there is a minimum here".
 
dnorric said:
This is why chemistry drives me crazy. There are so many exceptions to the rule, it hardly seems a science in comparison to physics. Thanks heaps for your help though

That's what happens when you study real systems instead of idealized models :p
 
dnorric said:
There are so many exceptions to the rule, it hardly seems a science in comparison to physics.

It depends on the selection of the rule. If the rule is "whichever system has the lowest energy, is the one observed in nature", this is not an exception.

But then you can't explain the system in the simple terms like "stable octet"...

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I think Mathematics and Physics are the ultimate weapons in dealing with Chemistry...
 
Since there are so many exceptions to the rule, perhaps it's just that we have yet to find the true and complete conditions of the rule. Just a thought...
 
There are many exceptions because the rule is oversimplified.

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There is a logic. Take some classes in quantum chemistry.
In the case of oxigen and sulfur the problem has to do with electron correlation.
Loosely speaking, in Oxigen the electrons are already so densely packed, that O2 tries to avoid contact with other oxigen atoms or molecules and instead develops a very strange double bond. In sulfur the orbitals are so much larger that electronic correlation is not a relevant topic any more. So it forms rather simplistic single bonds. The energetic differences between S4 S6 S8 to S_infinity are rather minute so that it is quite difficult to predict which one is actually most stable.
 

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