Covalent Bonding: Why Na 3s Electron Energy is Higher than Cl 3p

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SUMMARY

The energy of the 3s electron in sodium (Na) is significantly higher than that of the 3p electrons in chlorine (Cl) due to the greater electronegativity of Cl. According to inorganic chemistry principles, more electronegative atoms possess lower energy atomic orbitals. This disparity in energy levels prevents the formation of covalent bonds between Na and Cl, leading to the formation of ionic bonds instead. The conditions for covalent bonding—proper distance, similar symmetry, and similar energies—are not met in this case, as the energy difference between Na's 3s and Cl's 3p orbitals is too great.

PREREQUISITES
  • Understanding of electronegativity and its impact on atomic orbitals
  • Familiarity with ionic and covalent bonding concepts
  • Knowledge of molecular orbital theory
  • Basic principles of atomic structure and electron configuration
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  • Study the concept of electronegativity in detail, focusing on Pauling's scale
  • Explore molecular orbital theory and its implications for bonding
  • Investigate the rules for covalent bonding, particularly energy and symmetry considerations
  • Examine examples of ionic versus covalent compounds to understand their formation
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Clari
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Why the energy of 3s electron of Na is much higher than that of the 3p electrons of Cl?
 
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A simple rule of thumb from inorganic says that when comparing 2 atoms, the atom that is more electronegative will have atomic orbitals lower in energy when compared to another atom of lower electronegativity. Cl- is a lot more electronegative than Na so its orbitals are much lower than Na's atomic orbitals. Sodium chloride is also an ionic bond. If you look at it from a molecular orbital theory viewpoint, if the energies of orbitals are so different than the only bonding interaction that can occur is ionic bonding. In order for covalent bonding to occur you must satisfy 3 rules, proper distance, similar symmetry, and similar energies. While the 3p of the Cl and the 3s of the Na atom have similar symmetries, they do not satisfy the rule for similar energies. Thus no covalent bond can form, only an ionic bond.
 
Hello Gravenewworld, thank you very much for your clear explanation.. I understand why the energy of 3s orbital of Na is higher than that os 3s orbital of Cl...though I would like to ask: as 3p is different from 3s...why we can compare them this way..or is it that for elements with higher electronegativity, all their orbitals in the same shell is lower in energy than those atoms with higher energies?
 
Can you re-word your question? I don't really understand what you are asking.
 
im not sure by what he said seems to be true but i thought it was also (or) the size of the ions that you looked at when you had elements related. Top left most energetic bottom right least.

wait top right most, bottom left least
 
my questoin is "Why the energy of 3s electron of Na is much higher than that of the 3p electrons of Cl?", and you told me that it is because Na has lower electronegativity than Cl...but I suppose 3p is not 3s, so we can't compare them this way, isn't it? :smile:
 
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You can compare 3p orbitals with 3s orbitals because they are similar in symmetry. The question is will the 3pz orbital of the Cl atom and the 3s orbital of the Na atom interact to form a covalent bond? Whether they will form a covalent bond once again comes down to the 3 rules I listed earlier. We already said that they are similar in symmetry, and proper distance is usually never a problem. The reason that the 3pz and the 3s orbital do not interact to form a covalent bond is still because of the differences in energy between the two orbitals. The electronegativity difference is so great that it causes the energy differences between the 3pz and 3s orbitals to still be large, so without similar energies a covalent bond can not form, which is why NaCl forms from ionic bonding.
 
I understand now..Thanks~~ ^-^
 

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