Covariant and contravariant vecotr questions

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Covariant and contravariant vectors are discussed in relation to displacement and gradient vectors. Displacement vectors are described as tangent vectors, while the term "gradient vector" is questioned for its standard usage. The gradient of a function is defined as a tangent vector field with specific components, which varies based on the context of the function's domain. In the case of smooth manifolds, the gradient incorporates the metric's inverse components. Understanding these distinctions is crucial for grasping the underlying concepts in vector calculus and differential geometry.
drlang
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Hi

I am trying to learn about covariant and contravariant vectors and derivatives. The videos I have been watching talk about displacement vector as the basis for contravariant vectors and gradient as the basis for covariant vectors. Can somone tlel me the difference between displacemement and gradient vectors?
 
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This post and the ones linked to at the end explain some of what you need to know.

The term "displacement vector" doesn't make much sense to me. They are tangent vectors, nothing more, nothing less.
 
Hi Fredrik

I am using the terms he used.

Can you clarify the difference between tangent vector and gradient vector. Maybe that would help me.
 
I don't think "gradient vector" is a standard term, and I'm not sure what they mean by it. The gradient of a real-valued function f is defined as the tangent vector field with components ##\frac{\partial f}{\partial x^i}##, if we're talking about functions defined on ##\mathbb R^n##. So maybe that's what they mean. If we're talking about some arbitrary smooth manifold with a metric, then the gradient is defined as the vector field with components ##g^{ij}\frac{\partial f}{\partial x^j}##, where the ##g^{ij}## are the components of the inverse of the matrix of components of the metric, and the partial derivatives with respect to a coordinate system x are defined in one of the posts I linked to.

If you're only concerned with ##\mathbb R^n##, and not arbitrary smooth manifolds with metrics, then some things get simpler, but I still think it's worth the time read the posts I linked to, because they will make it easier to understand the terminology, and what's really going on in some definitions and calculations.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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