Covariant derivative from connections

  • Thread starter lavinia
  • Start date
  • #1
lavinia
Science Advisor
Gold Member
3,294
677
On a 2 dimensional Riemannian manifold how does one derive the covariant derivative from the connection 1 form on the tangent unit circle bundle?
 

Answers and Replies

  • #2
Ben Niehoff
Science Advisor
Gold Member
1,887
168
Its the same formula in any dimension. Let [itex]X = X^a e_a[/itex] be a vector field, where [itex]e_a[/itex] is an orthonormal frame. Then

[tex]\nabla X = (D X^a) \otimes e_a = (d X^a + \omega^a{}_b X^b) \otimes e_a[/tex]
 

Suggested for: Covariant derivative from connections

Replies
4
Views
1K
Replies
8
Views
2K
  • Last Post
Replies
6
Views
2K
Replies
5
Views
1K
Replies
15
Views
3K
  • Last Post
Replies
7
Views
2K
Replies
37
Views
6K
  • Last Post
Replies
7
Views
2K
  • Last Post
Replies
0
Views
1K
Replies
6
Views
2K
Top