Cramer's Rule and Determinants

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SUMMARY

This discussion focuses on using Cramer's Rule to solve a linear system represented by the equations 2x - y = -2 and x + 2y = 14. The user correctly identifies the coefficients to form a matrix and calculates the determinant as 5. They then attempt to find the values of x and y by substituting the constants into a new matrix and dividing by the original determinant, ultimately arriving at the correct solution of x = 2 and y = 6. The discussion confirms the user's approach and provides validation of their calculations.

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  • Understanding of linear equations and systems
  • Familiarity with matrix operations
  • Knowledge of determinants and their calculation
  • Proficiency in applying Cramer's Rule
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Homework Statement


Use Cramer's rule to solve the linear system.

Homework Equations


(only showing one, I think if one is explained I will figure out the rest)
2x - y = -2
x + 2y = 14

What I'm told I'm supposed to do, is to take the constants accompanying the variables and make a matrix out of them (2, -1, 1, 2)
Then find the determinant. To find the determinant, multiply diagonally down from the top left, and subtract that from the product of multiplying diagonally up from the bottom left. If I'm doing this right, I get 4 - (-1) which would give me 5. I found the determinant, and I have no idea what to do from there.

The Attempt at a Solution



What I think I'm supposed to do going off a rough memory, is take a matrix from the equaled values (-2 and 14) and put them on the right of the matrix, then use the Xs on the left. Find the determinant of that, and divide it by 5 (the determinant of the first one.) Of course, I really have no idea.
So if I do what I think I'm supposed to do (which I'm quite sure is the wrong thing) I get 28 - (-2) and get 30. 30 divided by 5 is 6. I think 6 is y.

So if y is 6, then 2x - 6 = -2, so 2x = 4. x = 2. So x is 2, x + 2y is 2 + 2(6) which is actually 14.

So maybe I got it right, but I'd like a bit of confirmation.
 
Last edited:
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You have the correct idea for the y coefficients. Instead of plugging in y into one of the equations and solving for x, you can just do the same substitution into the first column (leaving the second alone) and calculating its determinant.

If you're still confused, I can illustrate it with matrices, but everything you did was correct!
 

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