Crane Problem, Finding Angular Velocity

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SUMMARY

The discussion focuses on calculating the angular velocity components of a crane's boom in a fixed reference frame. The crane's boom rotates with an angular velocity of 0.08 rad/s around the vertical axis and an upward angular velocity of 0.03 rad/s. The user attempts to determine the components wx, wy, and wz using the equation w = w1 + Ω X w2, but encounters errors in their calculations. The correct approach requires careful consideration of both angular velocities and their respective accelerations.

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  • Understanding of angular velocity and its components
  • Familiarity with vector cross product operations
  • Knowledge of rotational dynamics and kinematics
  • Proficiency in using coordinate systems in physics
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This discussion is beneficial for physics students, mechanical engineers, and anyone involved in the analysis of rotating systems and crane operations.

jiffy
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Homework Statement



At the instant shown in the figure , the crane's boom has an angle = 33.0 and rotates around the vertical axis with angular velocity = 8.00×10^−2 radians/s that increases at the rate = 7.00×10^−2 radians/s^2. At the same instant, the crane's boom is rotating upward with angular velocity = 3.00×10^−2 that increases at the rate = 5.00×10^−2 . Determine wx, wy, and wz, the i, j, and k components of w, the boom's angular velocity in the fixed reference frame X, Y, Z. The translating-rotating reference frame, x, y, z, lines up with the fixed reference frame at the instant shown.

> The figure shows a crane with the z-axis vertical and the y-axis along the cranes boom. The angular velocity are all rotating counterclockwise. The origin is at the center of the crane.

Homework Equations



vp = wp X rp

vp is the velocity at a point
w is the angular velocity
rp is the position of the vector at a point

The Attempt at a Solution



w = w1 * w2 = (.03i + .08k)rad/s
\Omega = .08k rad/s
w = w_{12} + \Omega X w = (.05i + .07k) + .08k X (.03i + .08k)

=0.05i + 0.0024j + 0.07k

That was my final answer but it is wrong.
 
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How are you taking the acceleration of the crane into account?
 
I'm taking into account the acceleration in my equation but the answer is still not correct:

w = + \Omega X w = (.05i + .07k) + .08k X (.03i + .08k)
 

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