1. The problem statement, all variables and given/known data A large empty crate, with its lid in place, has a 9.50 kg mass hanging from a string attached to the center of the lid. If the crate were sitting (at rest) on a flat surface, the string would simply hang straight down such that the mass would not be touching the floor of the crate. The crate is now pushed up a frictionless 10.0 degree slope with an acceleration of 2.25 m/s^2. During the push, what angle does the string make with the lid of the crate? Hint: you will need to solve two equations in two unknowns. 2. Relevant equations f=ma newton's 2nd law 3. The attempt at a solution I found the force required to push it up the ramp f= 9.8(9.5)sin10 = 16.2N Not sure if i even need that but i did it anyways. so i really have no idea what 2 equations i need to get in order to solve the angle of the string? can anyone help me on this please. thank you
Hi mybrohshi5! The acceleration of the mass will be the same as that of the crate (and in the same direction). And there are two forces on the mass. So use good ol' Newton's second law on the mass … what do you get?
well the two forces would be the force due to gravity (its weight) and the normal force is that correct? im a little confused about what i need to find from what you just stated above. thank you for any further explanations
Hi mybrohshi5! Normal force? Normal to what? It's not touching anything. Add the two forces (one is unknown, so just give it a letter), and use F = ma.
i thought there was a normal force but i guess cause it frictionless there is not a normal force? im sorry im so lost right now about adding the two forces (one is unknown) and use f = ma
Are you talking about the crate? I'm asking about the mass hanging, inside it. What is the F_{total} = ma equation for the mass?
sorry i was reading the question completely wrong for some reason i am having a really hard time wrapping my head around what is going on still though and how to find these equations :( the mass will have two forces on it correct. one force will be the weight and the other force will be the force parallel to the ramp just in the opposite direction? im just really confused.... do i need to include tension in these two equations that i am trying to find?
You are confused, aren't you? Yes, the tension is the only other force on the mass. ok, so solve the vector equation: mg + T = ma. (and get some sleep! :zzz:)
goodness i am not exactly sure. i am so confused on how to get two equations for this. ok, so solve the vector equation: mg + T = ma. when you said this should i solve it for the tension?
Yes. T has magnitude and direction (and the question only asks you for the direction). You will need to take components in a suitable direction, of both a and the forces. You have a choice of three pairs of components: horizontal/vertical slope/normal string/perpendicular-to-string … which do you think will be quickest?
my guess would be string/perpendicular to the string? but maybe would it be slope/normal because the angle i am trying to find has to deal with the slope and the crate....
Yes, that will be quicker because you don't want to find the magnitude of T, so you can avoid it by using components perpendicular to it.
so in the equation mg + T = ma do i replace T with the components perpendicular to the string? gosh i feel so stupid right now. i cannot even begin to explain how confused i am about this whole problem :( am i just making it much more difficult than it actually is because thats what i feel i am doing :(
tiny-tim is there any other way you could maybe explain this to me a little differently? i dont seem to get it and its the only one on my homework i cant get :(