Crate Pushed up an Incline problem

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SUMMARY

The discussion focuses on calculating the work done by a person pushing a 27 kg crate up a ramp with a coefficient of kinetic friction of 0.24 over a distance of 30 meters. The solution involves determining the forces acting on the crate, specifically the gravitational force component along the ramp and the frictional force. The work done is calculated by summing the forces and multiplying by the displacement, confirming that the crate moves at a constant velocity.

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Homework Statement


A crate of mass 27 kg is pushed up a ramp by a person, as shown in the figure below. Assume the coefficient of kinetic friction between the crate and the ramp is .24. Calculate the work done by the person in pushing the crate a distance of 30 m as measured along the ramp. Assume that the crate moves with at a constant velocity.

Homework Equations


The Attempt at a Solution


I've tried a few different ways and I know something is missing but I can't quite figure out what. Here's what I've tried.

1. (27kg)(9.8)(sin30)=

2. (.24µk)(27kg)(9.8)(cos30)=

3. (.24µk(27kg)(cos30)(30m)=
 
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Hi Manda 24, welcome to PF.

The cart will move with uniform velocity when it overcomes the forces given by 1. and 2. in your attempt.
To find the work done, add 1 and 2 and multiply by the displacement.
 
Thanks, that helped.
 

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