Help please simple Physics frictionless crate on ramp problem Urgent?

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SUMMARY

The discussion focuses on solving a physics problem involving a crate of mass 100 kg being pushed up a frictionless ramp at an angle of 30.0°. The horizontal force F required to maintain constant speed is calculated using the equation F = mg sin θ, resulting in a force of 566 N after dividing by cos 30. Additionally, the normal force N acting on the crate from the ramp is determined using the equation N = mg cos θ + F sin θ, yielding a value of 1131 N. The breakdown of forces in both the x and y directions is essential for understanding the solution.

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Help please! simple Physics frictionless crate on ramp problem! Urgent!?

A crate of mass m = 100 kg is pushed at constant speed up a frictionless ramp (θ = 30.0°) by a horizontal force F. What are the magnitudes of (a) F and (b) the force on the crate from the ramp?

So my teacher did this problem but I do not understand

here's what he did:

a) mg sin θ = 100(9.8)sin30 = 490 N (I understand this part)
490 / cos30 = 566N <--Why divide by cos 30 to get the correct answer?!?

b) N = mg cos θ + F sin θ
100(9.8)cos30 + 566sin30 = 1131N <--I do not understand part b) at all. Can someone explain step by step on what we are doing on part b).

help please!
 
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help i have a test tmrw!
 


Choose the x-axis as the axis parallel to the plane and the y-axis perpendicular to the plane. The applied force is horizontal and you can break it up onto its x and y components. Then use Newton 1 in the x direction and Newton 1 in the y direction.
 

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