Creating a grid type 3D data array from data points

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The discussion focuses on creating a 3D numpy array from specified ranges of data points in the form of (X, Y, Z). The ranges provided are X = (0, 5), Y = (0, 3), and Z = (0, 2), resulting in a total of 72 data points. While there is no direct numpy function to achieve this, a list comprehension can be used effectively to generate the desired array format. The suggested command is: np.array([[x, y, z] for x in range(6) for y in range(4) for z in range(3)]).

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Arman777
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I have a 3 data column ##(X, Y, Z)## ranges from ##(min, max)##. For example,

##X = (0, 5)##, ##Y=(0, 3)##, ##Z=(0, 2)##. By using them I need to create a numpy array in the form of

##[(0, 0, 0), (0, 0, 1), (0, 0, 2), (0, 1, 0), (0, 1, 1), (0, 1, 2), (0, 2, 0)...]##

So in total there will be ##6 \times 4 \times 3 = 72## data points.

Is there a simple command to do this ?
 
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numpy arrays cannot hold tuples

If you want to create a 2D 72 x 3 numpy array similar to that there is no simple function*; this is a typical exercise for any aspiring coder.

* the np.indices, np.mgrid and np.ogrid functions do something similar, but I don't think there is anything that does exactly this.

Edit: I suppose you could view a list comprehension as a "simple command" (but the word "command" is not appropriate here):
Python:
np.array([[x, y, z] for x in range(6) for y in range(4) for z in range(3)])
 
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