Critical Points & their Nature of a Multivariable Function

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Homework Help Overview

The discussion revolves around finding the critical points and their nature for the multivariable function f(x,y) = xy(9x^2 + 3y^2 -16). Participants are exploring the process of differentiation and the implications of critical points in a multivariable context.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the differentiation of the function and the resulting equations for critical points. Questions arise regarding the simultaneous solution of the derived equations and the geometric interpretation of the results.

Discussion Status

Some participants have provided guidance on setting the partial derivatives to zero and solving the resulting equations. There is acknowledgment of multiple stationary points, and the discussion includes considerations of geometric representations related to the equations.

Contextual Notes

Participants are navigating the complexity of multivariable calculus and the implications of their findings, including the potential for multiple solutions and the nature of critical points.

wowmaths
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Homework Statement


f(x,y) = xy(9x^2 + 3y^2 -16)

Find the critical points of the function and their nature (local maximum, local minimum or saddle)


Homework Equations





The Attempt at a Solution


I have partially differentiated the equation into:

fx = 27yx^2* + 3y^3 -16y
fy = 9x^3 + 9xy^2 - 16x

How do I go on from there though?
 
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Hey there, welcome to the forum.

So, recall that a critical point of a function f(x) occurs when the derivative f'(x) = 0.

Now translating that to the multivariate case is not very different. Set fx = 0 and fy = 0 and then solve for your critical points.
 
wowmaths said:

Homework Statement


f(x,y) = xy(9x^2 + 3y^2 -16)

Find the critical points of the function and their nature (local maximum, local minimum or saddle)

Homework Equations


The Attempt at a Solution


I have partially differentiated the equation into:

fx = 27yx^2* + 3y^3 -16y
fy = 9x^3 + 9xy^2 - 16x

How do I go on from there though?

You solve the equations
27*y*x^2 + 3*y^3 - 16*y = 0
9*x^3 + 9*x*y^2 - 16*x = 0.
The first one says either y = 0 or 27*x^2 + 3*y^2 - 16 = 0, and this last one is the equation of an ellipse in (x,y) space. The second one says either x = 0 or 9*x^2 + 9*y^2 -16 = 0. What kind of geometric figure does that describe in (x,y)-space?

RGV
 
Last edited:
Zondrina said:
Hey there, welcome to the forum.

So, recall that a critical point of a function f(x) occurs when the derivative f'(x) = 0.

Now translating that to the multivariate case is not very different. Set fx = 0 and fy = 0 and then solve for your critical points.

Ray Vickson said:
You solve the equations
27*y*x^2 + 3*y^3 - 16*y = 0
9*x^3 + 9*x*y^2 - 16*x = 0.
The first one says either y = 0 or 27*x^2 + 3*y^2 - 16 = 0, and this last one is the equation of an ellipse in (x,y) space. The second one says either x = 0 or 9*x^2 + 9*y^2 -16 = 0. What kind of geometric figure does that describe in (x,y)-space?

RGV

Thanks a lot for the welcome and the help. Greatly appreciated.
Just a question:
For both the equations:
fx = 27*y*x^2 + 3*y^3 -16*y = 0
and
fy = 9*x^3 + 9*x*y^2 - 16*x = 0

Am I supposed to solve both equations simultaneously to find the stationary points?

I tried using a calculator to solve both equations simultaneously and I've gotten 9 stationary points.

Am I on the right track?
 
Ill give you a hint, use elimination to solve both. Solve for y in the first equation to get y=0 and y = ± something else.
 
wowmaths said:
Thanks a lot for the welcome and the help. Greatly appreciated.
Just a question:
For both the equations:
fx = 27*y*x^2 + 3*y^3 -16*y = 0
and
fy = 9*x^3 + 9*x*y^2 - 16*x = 0

Am I supposed to solve both equations simultaneously to find the stationary points?

I tried using a calculator to solve both equations simultaneously and I've gotten 9 stationary points.

Am I on the right track?

Answer to both questions is yes. The geometric representation I suggested before shows why there are 9 solution points.

RGV
 

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