Critically Damped System - Viscous force

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SUMMARY

The discussion focuses on the dynamics of a critically damped system involving a mass on a spring, where the viscous force is represented by -bv. Participants confirm that for critical damping to occur, the relationship $$b=2m \sqrt{(g/Δx)}$$ must hold true. The conversation highlights the importance of distinguishing between oscillation caused by the spring-mass system and the role of gravity, which acts as a constant force. Additionally, it clarifies that while critical damping minimizes oscillation, it may still allow for some overshoot compared to overdamped systems.

PREREQUISITES
  • Understanding of Hooke's Law and spring dynamics
  • Familiarity with the concepts of damping in mechanical systems
  • Knowledge of differential equations and their applications in physics
  • Basic grasp of gravitational forces and their effects on oscillatory motion
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  • Study the derivation of the differential equation for damped harmonic motion
  • Explore the differences between critically damped and overdamped systems
  • Learn about the implications of damping ratios in mechanical systems
  • Investigate the role of initial conditions in the behavior of oscillatory systems
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dumbdumNotSmart
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Homework Statement


You got a plate hanging from a spring (hookes law: k) with a viscous force acting on it, -bv.

If we place a mass on the plate, gravity will cause it to oscillate.

Prove that if we want the plate to oscillate as little as possible (Crticial damping, no?), then $$b=2m \sqrt{(g/Δx)}$$

Homework Equations


$$F=ma $$

The Attempt at a Solution


I cannot for the life of me get the differential equation right. Given the conditions I assume they want me to find b for a critically damped system (also answer looks like so). This is my best try

$$ma=-bv +mg -kx$$

Since g is not accompanied by x, dx or d2x it will be part of the particular solution, not the homogenous. What am I missing here?
 
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Gravity is a constant, therefore it will contribute a constant, nonoscillatory terms to the solution. Why do you think you need to focus on the homogeneous solution only?
 
dumbdumNotSmart said:

Homework Statement


You got a plate hanging from a spring (hookes law: k) with a viscous force acting on it, -bv.

If we place a mass on the plate, gravity will cause it to oscillate.

Prove that if we want the plate to oscillate as little as possible (Crticial damping, no?), then $$b=2m \sqrt{(g/Δx)}$$
Is this the actual wording of the problem? It's a bit misleading to say gravity will cause the system to oscillate since it's the spring and mass which results in the oscillation. Also, I wouldn't equate "oscillate as little as possible" with "critical damping." A highly overdamped system won't oscillate either, but a critically damped system could still allow some overshoot. That motion is arguably allowing "more oscillation" than the overdamped system.
 
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Dr.D said:
Gravity is a constant, therefore it will contribute a constant, nonoscillatory terms to the solution. Why do you think you need to focus on the homogeneous solution only?

Mainly because the condition for minimum time to reach equilibrium is given by a critically damped system. If this is so then it must be shown in the homogenous equation.

vela said:
Is this the actual wording of the problem? It's a bit misleading to say gravity will cause the system to oscillate since it's the spring and mass which results in the oscillation. Also, I wouldn't equate "oscillate as little as possible" with "critical damping." A highly overdamped system won't oscillate either, but a critically damped system could still allow some overshoot. That motion is arguably allowing "more oscillation" than the overdamped system.

The question is not phrased that way. I just wanted to make it clear that the initial impulse was given by gravity. The question does state that the system has to reach equilibrium sooner than any other system. According to my reading (Tipler & Mosca Physics textbook) a critically damped system will return to it's resting state sooner than any other system. A overdamped system will settle on the resting state but will take more time.
 

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