Cross/Dot Products in Physics: Work, Torque & Impulse

  • Context: Undergrad 
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SUMMARY

The discussion focuses on the definitions and applications of Work, Torque, and Impulse in physics, specifically highlighting the equations Work = Fdcos(θ) and Torque = rFsin(θ). The conversation clarifies that Work is calculated using the dot product of force and displacement, integrating over the path to determine the effective force along the motion. Additionally, it emphasizes the relationship between Impulse and Work, noting that Impulse is the integral of Work done over time. The discussion also invites exploration of other physics concepts involving cross and dot products.

PREREQUISITES
  • Understanding of vector mathematics, specifically dot and cross products
  • Familiarity with basic physics concepts such as force, distance, and angles
  • Knowledge of integral calculus as it applies to physics
  • Basic understanding of mechanics, particularly Work and Torque
NEXT STEPS
  • Study the application of vector calculus in physics problems
  • Learn about the relationship between Work and Energy in mechanics
  • Explore the concept of Impulse and its applications in collision physics
  • Investigate other mechanics topics involving cross products, such as angular momentum
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in deepening their understanding of mechanics, particularly in the context of Work, Torque, and Impulse calculations.

danyo
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Hello, I was thinking about the definition of Work to equal Fdcos(theta) , where F is force and d is the distance traveled; and that torque is rFsin(theta) whereas r is radius, and F is the force applied, and theta is the angle that the force vector makes with the object. I understand the geometric reasoning to the equation for torque above, but not as for work. Could you help me with some insight on the theory behind this? (Also I'm interested as to how Impulse is the integral of Work done). And what other things in mechanics or any branch of physics involve these cross products or dot products?

Thanks in advance, and my apologies for the very basic questions; I'm relatively new to physics, but I'm excited to familiarize myself with what goes on behind the problems I solve and the equations I use on my homework problems. Cheers, Daniel. =)
 
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\theta is the angle between the direction of the applied force and the path of motion of the object (not the angle that the force makes with the object). Work is defined as the amount of force applied over the path of motion. So we take the dot product of force and the path of motion (and integrate over the path to find work) to find the component of the force that was actually applied along the path. In scalar form, this is equal to F*\cos(\theta).
 

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