Cross product and dot product scalars

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SUMMARY

The discussion centers on calculating the expression (d1 + d2) · (d1 × 4d2) using the vectors d1 = 4i - 10j + 2k and d2 = 9i - 10j + 6k. Participants clarify the process of obtaining the dot product as a scalar, emphasizing that the result of the dot product must be a single number. The correct approach involves first calculating the sum of the vectors, followed by the cross product, and finally the dot product. The final scalar result is confirmed to be -3200 after correcting earlier miscalculations.

PREREQUISITES
  • Understanding of vector operations, specifically cross product and dot product.
  • Familiarity with vector notation in three-dimensional space.
  • Ability to perform arithmetic operations on vectors.
  • Knowledge of scalar and vector quantities in linear algebra.
NEXT STEPS
  • Review the properties of vector addition and scalar multiplication.
  • Learn how to compute the cross product of two vectors in detail.
  • Study the dot product and its applications in physics and engineering.
  • Practice problems involving vector operations to solidify understanding.
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Students studying linear algebra, physics enthusiasts, and anyone looking to deepen their understanding of vector operations and their applications in mathematics and engineering.

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Homework Statement


If d1 = 4i - 10j + 2k and d2 = 9i - 10j + 6k, then what is (d1 + d2) · (d1 × 4d2)?


Homework Equations


Know how to do the cross product and dot product

The Attempt at a Solution


For the answer i got 9.6i + 56j -127.68k. How do i express that as a scalar for an online program that only has one box to type in?
 
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Your answer should be a scalar anyway if you had to take the dot product (commonly known as the scalar product). I suggest you check your answer.
 
I didnt think my answer was wrong though?
 
If you take the dot product of two vectors then the answer will be a scalar not a vector. If you post what you've done it'll be easier to identify where you went wrong.
 
First i calculated the quantity of d1+d2 and got 13i + 0j +8k. Then i went to the other side of the problem and distributed the 4 to the d2 terms and got a result of 36i - 40j + 24k. After that, i took the cross product of d1 and 4d2 and got -160i -24j - 200k. Then i took the dot product and got -2080i - 1600k (sorry i posted the wrong answer the first time, my bad)
 
For the addition of d1 and d2, -10 +(-10) does not equal 0.

For the cross product, that should be +200k.

The dot product of two vectors is:

\mathbf{a}\cdot \mathbf{b} = a_x b_x + a_y b_y + a_z b_z
 
Last edited:
so then when i add that up, it equals one number? for example if i had axbx=3, ayby=4 and azbz=2, then i would have something that resembles 3+4+2 and would i use 9 for the answer?
 
yes, that's correct.
 
i got -3200 for my final answer, but that seems wrong..
 
  • #10
Again if you post exactly what you've done when computing the dot product it will be easier to advise you where you went wrong.
 
  • #11
after doing the cross product for d1xd2, i got -160i -24j -200k. After that, i multiplied by the sum i got for the d1+d2 section. So in the end, i multiplied -160 times 13, -24 times -20, and -200 times 8. Then i had -2080 + 480 - 1600
 
  • #12
If you look in my previous post I said that after the cross product you should have +200k not -200k.
 
  • #13
TS656577 said:

Homework Statement


If d1 = 4i - 10j + 2k and d2 = 9i - 10j + 6k, then what is (d1 + d2) · (d1 × 4d2)?


Homework Equations


Know how to do the cross product and dot product

The Attempt at a Solution


For the answer i got 9.6i + 56j -127.68k. How do i express that as a scalar for an online program that only has one box to type in?

remeber that the cross product is something like;

[-,-]: VxV----->V; \\ V=vector space

so gives you back another vector;

while the dot product (generally an inner product) is something like;

(-,-): VxV------>C \\ C=complex field

know how to make both in an euclidean orthonormal basis and you'll get your answer;

regards;
marco;
 
  • #14
got it, thanks guys...sorry for bein dumb (sick last few days)
 

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