Crow flying to destination (vector problem)

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SUMMARY

The discussion focuses on a vector problem involving a crow's flight to a destination 80 m west. The first displacement is 80 m at an angle of 65° west of north, leading to the calculation of the second displacement's magnitude and direction. The magnitude of the second displacement is determined to be 88.3 m, while its direction is calculated to be 295° west of north. The use of trigonometric functions and the Pythagorean theorem is essential for solving this problem.

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Homework Statement


A crow flies in two successive displacements to a point that is 80 m to the west. Its first displacement is 80 m in a direction θ1 = 65° west of north.

a)What is the magnitude of its second displacement?

b)What is its direction of its second displacement measured by the angle θ2 measured west from north?


Homework Equations





The Attempt at a Solution



90-65= 25° N of W

cos25°= 80/c --> then c= 80/cos25°= 88.3m

c²=a²+b²

b=√(c²-a²)
b=√((88.3)²-(80)²)
b=37.4m

180°= 25°+90²+Θ
Θx=65°

360°-65°=

295° W of N
 
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Hello Patrick, and welcome to PF.

In these cases a sketch or a drawing is a big help. I, for instance, can't understand what the c you are calculating, stands for.

I can understand the 25°, though, and I can calculate how much of the 80 m in the westward direction has been covered (call it A). Also how much in the northward direction (call it B). So all I, crow, have to do then is to go west the remainder of the 80 m and south the same distance B. Gives me a magnitude using Pythagoras and an angle via an arctangent.
 
What is ALWAYS advised here is that when you want help with such a problem, SHOW YOUR DIAGRAM. That let's us know what you are doing/thinking and might readily lead to our being able to help you.
 

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