Cubic equation with two unknown coefficients

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MegaDeth
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Homework Statement



x^3 +px^2 + 56x + q = 0I've attempted the first part but I have no idea what to do next. I know usually you'd have 3 new roots inn terms of alpha, beta and gamma but they're not given.

Homework Equations



Given that the three roots are all positive and are the first free terms of a geometric series with common ratio 2,

a. find the three roots of the equation.

b. find the values of p and q.

The Attempt at a Solution



I've work out the old roots,

roots one at a time = -p

roots two at a time = 56

product = -q
 
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Hi MegaDeth! :smile:
MegaDeth said:
Given that the three roots are all positive and are the first free terms of a geometric series with common ratio 2 …

(i assume you mean the first three terms? :wink:)

start by calling the smallest root "r" …

then you know what the other two roots are :wink:
 
tiny-tim said:
Hi MegaDeth! :smile:


(i assume you mean the first three terms? :wink:)

start by calling the smallest root "r" …

then you know what the other two roots are :wink:


Oh god, that's embarrassing. I didn't notice that mistake.

Ok, so the roots would be: r, r+2 and r+4? If so, how would I use these to find p and q?
 
Sorry but I'm not familiar with this method. I don't know how to do it. :(