Curl of field in cylindrical coordinates

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
5 replies · 3K views
FOIWATER
Gold Member
Messages
434
Reaction score
12
I am asked to compute the Curl of a vector field in cylindrical coordinates,

I apologize for not being able to type the formula here I do not have that program.

I do not see how the the 1/rho outside the determinant calculation is being carried in?

Not for the specific problem - but for curl in other coordinates in general.

1/rho det(arho rho*bphi cz
d/drho d/dphi d/dz
Arho rho*Atheta Az)

I'm staring at it a long time, - I don't see how it expands as it does..

Any help appreciated.
 
Physics news on Phys.org
How did you come by a 1/r outside the determinant?

The determinant for computing curl A is

1r/r 1ψ k/r
∂/∂r ∂/∂ψ ∂/∂z
Ar rAψ Az

I used r instead of rho and ψ instead of phi since phi is not available on the PF symbol table.

There is no 1/r term in front of the determinant.
 
There is for cylindrical coordinates

At least in most things I have come across

I am referencing the 5th edition of "elements of electromagnetics"
 
FOIWATER said:
There is for cylindrical coordinates

At least in most things I have come across

I am referencing the 5th edition of "elements of electromagnetics"

What I gave you and what you said are the same thing. Your version brings 1/r outside the determinant, then multiplies all my terms by r. It's a dumb way of giving the determinant in my opinion, but it's correct also.

What did you say was your problem with it again? I couldn''t figure out what your confusion is.
 
Only the row by which cofactors are expanded, though?
 
nvm I understand it now, thanks