Curl of tensor * non-constant vector

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SUMMARY

The discussion centers on the relationship between the curl of a tensor multiplied by a non-constant vector field and its implications in vector calculus. Specifically, the user inquires whether the equation curl(Tw) = curl(T)w holds true when w is defined as the gradient of a scalar field u, making it an irrotational vector field. The consensus is that the validity of this equation does not depend on the properties of w, as the curl operator's vector structure does not directly influence w due to the contraction with the tensor indices.

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  • Familiarity with tensor algebra and second-order tensors.
  • Knowledge of gradient operations and irrotational vector fields.
  • Proficiency in index notation for tensor equations.
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This discussion is beneficial for mathematicians, physicists, and engineers who work with vector calculus and tensor analysis, particularly those dealing with fluid dynamics and continuum mechanics.

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I know by definition that if T is a 2nd order tensor and v is a vector,
curl(Tv)=curl(T)v

but what if instead of constant vector v, I have w=grad(u), not constant but obviously an irrotational vector field. Is this still true:
curl(Tw)=curl(T)w ?

My guess is yes since curl(w)=0 but have no verification. Please advise. Thank you.
 
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Are you familiar with index notation? If not I suggest learning it because it will make your tensor equations much more straightforward to interpret.

To answer your question, the answer will not depend on curl(w). The vector structure of the curl operator is not directly affecting w, since the w is contracted with one of the tensor indices.
 

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