Current Decay in an R-L Circuit

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SUMMARY

The discussion centers on calculating the time it takes for the stored energy in an R-L circuit to reach half of its maximum value after closing the switch. The solenoid parameters include a length of 18.5 cm, a diameter of 2.20 cm, and 545 windings, resulting in an inductance (L) of 7.66 x 10-4 H. The maximum energy (U) calculated is 5.99 x 10-4 J, but the user incorrectly applies the decay formula for energy, leading to a time (t) of 1.32 x 10-5 seconds instead of the correct value of 4.71 x 10-5 seconds. The correct approach involves determining the current as a function of time to accurately compute the energy stored in the inductor.

PREREQUISITES
  • Understanding of R-L circuit dynamics
  • Familiarity with inductance calculations using the formula L = (μ0N2A)/l
  • Knowledge of energy stored in inductors, U = 0.5*L*I2
  • Experience with exponential decay equations in electrical circuits
NEXT STEPS
  • Study the derivation and application of the current function in R-L circuits
  • Learn about the energy storage dynamics in inductors
  • Explore the differences between energy decay and energy growth in electrical circuits
  • Investigate the impact of resistance on time constants in R-L circuits
USEFUL FOR

Physics students, electrical engineers, and anyone studying R-L circuits and energy dynamics in electrical systems will benefit from this discussion.

sdalglish13
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I was trying to solve this problem the other day for my physics class and I keep getting the wrong answer. The problem is as follows:

An ideal solenoid is 18.5 cm long, has a circular cross-section 2.20 cm in diameter, and contains 545 equally spaced thin windings. This solenoid is connected in a series circuit with a 15 ohm resistor, a battery of internal resistance ohms and open-circuit terminal voltage of 25 V, and an open switch. (Note u = 4*(pi)*10-7 T *m/A)

How long after closing the switch will it take for the stored energy in the solenoid to reach 1/2 of its maximum value?


So this is what I did:

L = (u0N2A)/l

where L = inductance in Henry
N = number of turns
A = area of cross-section
l = length in meters

L = (4*(pi)*10-7 )(5452)(3.8*10-4)
.185

L = 7.66 *10-4 H

Then I found the current I:

I = emf/R

where emf = electromotive force/voltage
R = resistance

I = 25 Volts/(15 ohms + 5 ohms) = 1.25 Amps

Next I used the energy equation to find the maximum energy:

U = 0.5*L*I2

where U = energy
L = inductance
I = current

U = 0.5*(7.66 *10-4)*(1.252)
U = 5.99*10-4 J


Then I don't know where to go from there to find time. I already tried an equation I found in my textbook...

U = U0e-2*(R/L)*t

t = -ln(.5)*L/(2R)
t = -ln(.5)*(7.66 *10-4)/(2*(15+5))
t = 1.32*10-5 sec

and solved for t that way, but I keep getting 1.32*10-5 sec, when the answer should be t = 4.71 *10-5. I know t = 4.71 *10-5 is the correct answer because it came off of the answer sheet for a review.

Can anyone shed some light on what I am doing right/wrong?
 
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You need to find the current as a function of time and use it to calculate the energy stored in the inductor as a function of time.

The equation you tried doesn't apply to this situation. For one, it starts at U0 and decays to 0, but in this circuit, the energy starts at 0 and increases to the max value you found as t goes to infinity.
 

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