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Current division in a series-parallel circuit

  1. May 15, 2017 #1
    1. The problem statement, all variables and given/known data
    Determine the current through each circuit element
    2. Relevant equations
    V = IR (Ohm's Law),

    3. The attempt at a solution
    I1 is .06A after plugging 6V and 100 ohms into V = IR, but I can't figure out the rest, because I don't know how the current splits. The left path obviously has less resistance, so more current will flow through it, but I don't know how to calculate how the .06A will split because of that. Since that 50 ohm wire connects the 2 paths i don't know how it affects the total resistances of each.
     

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  2. jcsd
  3. May 15, 2017 #2

    BvU

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    Hello Ketchup, :welcome:

    It's a little more complicated than you make it out: 6V/100##\Omega## isn't right, because that would mean 6 V over 100##\Omega## and zero V over the rest of the circuit -- so zero current ##\Rightarrow## contradiction !

    You know about Kirchoffs laws ? This exercise assumes you do -- or else that you discover one of them !
     
  4. May 15, 2017 #3

    scottdave

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