# Current division in a series-parallel circuit

1. May 15, 2017

### Ketchup4684

1. The problem statement, all variables and given/known data
Determine the current through each circuit element
2. Relevant equations
V = IR (Ohm's Law),

3. The attempt at a solution
I1 is .06A after plugging 6V and 100 ohms into V = IR, but I can't figure out the rest, because I don't know how the current splits. The left path obviously has less resistance, so more current will flow through it, but I don't know how to calculate how the .06A will split because of that. Since that 50 ohm wire connects the 2 paths i don't know how it affects the total resistances of each.

#### Attached Files:

• ###### series-paraller circuit.png
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2. May 15, 2017

### BvU

Hello Ketchup,

It's a little more complicated than you make it out: 6V/100$\Omega$ isn't right, because that would mean 6 V over 100$\Omega$ and zero V over the rest of the circuit -- so zero current $\Rightarrow$ contradiction !

You know about Kirchoffs laws ? This exercise assumes you do -- or else that you discover one of them !

3. May 15, 2017