Current Electricity: Force Calcs & Plate Impact

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SUMMARY

The discussion focuses on the calculations involved in determining the motion of a positively charged particle in an electric field between two parallel plates. The particle, with a mass of 35.6 mg and a charge of +8.40 nC, has an initial horizontal velocity of 29.6 m/s. Key calculations include the net force equation, Fnet = Fe + Fg, and the acceleration formula, a = (qE - mg)/m. Participants confirmed the correct interpretation of nano-Coulombs and the relevance of gravitational force in the particle's motion.

PREREQUISITES
  • Understanding of electric fields and forces (Fe)
  • Basic knowledge of kinematics and dynamics
  • Familiarity with units of charge, specifically nano-Coulombs (nC)
  • Ability to perform calculations involving mass and acceleration
NEXT STEPS
  • Study the principles of electric fields and their effects on charged particles
  • Learn about the equations of motion in electric fields
  • Explore the concept of gravitational force in relation to charged particles
  • Review the conversion of units, particularly in electrostatics
USEFUL FOR

Students in physics, educators teaching electricity concepts, and anyone interested in the dynamics of charged particles in electric fields.

Kylah
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[SOLVED] Current Electricity

1. A positively charged particle enters an evacuated region between two parallel plates with an initial horizontal velocity of 29.6 m/s, as shown in the following diagram. The particle has a mass of 35.6 mg and a charge of +8.40 nC.
i168.photobucket.com/albums/u173/pleasetheworld/physicss.jpg

A) Will either the force of gravity or the force of air resistance play a role in the motion on this particle? Support your answer.

I assumed the force of gravity would act downwards on the particle. I'm not sure though. Haha.

B) Do the necessary force calculations to determine which plate the particle will strike. Begin your solultion with a labelled diagram.
So I did the diagram, and this is what I've done so far with the calculations:

Fnet= Fe + Fg
Fnet= |Fe|, up + |Fg|, down
Fnet= +|Fe| + -|Fg|
ma= q|E| - mg
a = (qE - mg)/m

I assume all I need to do is plug in values, but, I have a rather stupid question, what does nC mean? Does it just mean I need to change the +8.40 value to 8.40 x 10^-9?

Do I appear to have the write idea with the calculations?
 
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1) Why do you think gravity would effect the particle? Saying "I'm not sure" is ok, but for me to help you I have to know why you think so.

2) nC is nano-Coulomb, so you are right, just multiply it by 10^-9.

3) Your math looks correct. :smile:
 

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