Current flowing in a cylinder and induced EMF

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SUMMARY

The discussion focuses on the relationship between current flow in a cylinder and the induced electromotive force (EMF). The induced EMF is calculated using the formula E = -dΦ/dt, where Φ is the magnetic flux. The magnetic field inside the cylinder is determined to be μ0i/l, which is consistent with the behavior of a solenoid. Participants clarify the equivalent resistance of the cylinder and address a sign error in the current equation, ultimately confirming the correct formulation as iR + E = 0.

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  • Understanding of electromagnetic induction principles
  • Familiarity with Ampere's circuital law
  • Knowledge of resistance calculations in cylindrical conductors
  • Proficiency in using the formula for magnetic fields in solenoids
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Jahnavi
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Homework Statement


cylinder.png

options.png


Homework Equations

The Attempt at a Solution



The current will decrease , as a result an EMF will be induced in the cylinder .

The EMF induced E = -dΦ/dt

I am assuming magnetic field through the cylinder to be same as that at the center of the a current carrying coil which is given by μ0i/2r .

E = -μ0πrdi/(2dt)

I tried to calculate equivalent resistance .

I think we can consider thin cylinder material as a thin sheet of breadth 'l' , length '2πr' and thickness 'd' .

It can be divided into thin wires of length '2πr' , width dx and thickness 'd'

Current is flowing across the breadth .

Consider a very thin section of wire of width dx at a distance x across the breadth from one end .

All these thin wires are in parallel .

Their equivalent resistance turns out to be ρ2πr/ld .

So , the resistance across which the current is flowing is R = ρ2πr/ld .

The current equation would be iR + E = 0 .

iR - μ0πrdi/(2dt) = 0

ρ2πri/ld - μ0πrdi/(2dt) = 0

Is the equation correct ?
 

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Why is the current equation iR + E = 0? Should it not be iR = E?
 
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Jahnavi said:
I am assuming magnetic field through the cylinder to be same as that at the center of the a current carrying coil which is given by μ0i/2r .
No. Think solenoid.

So , the resistance across which the current is flowing is R = ρ2πr/ld .
That looks good to me.

The current equation would be iR + E = 0 .

iR - μ0πrdi/(2dt) = 0

As @Chandra Prayaga pointed out, there seems to be a sign problem here. Note that your equation would imply that di/dt is positive; i.e., the current would increase instead of decrease.
 
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Thank you TSny .

TSny said:
No. Think solenoid.

You are right :smile:

Magnetic field inside a solenoid is μ0ni .

How would I find 'n' of the equivalent solenoid ? 'n' is the number of terms per unit length .
 
Solenoid consists of wires. This cylinder has a continuous current distribution thus evaluate using Ampere's circuital law.

B.2πr = μ0
That gives B =μ0i/2πr
 
Note that in ##\mu_0ni##, ##\, i## is the current in one turn. Try to interpret the meaning of ##ni##.
 
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TSny said:
Note that in ##\mu_0ni##, ##\, i## is the current in one turn. Try to interpret the meaning of ##ni##.

Wow !

I didn't think in this way .

Magnetic field inside cylinder would be μ0i/l .

This gives us option 2) .

Is that correct ?
 
Jahnavi said:
Magnetic field inside cylinder would be μ0i/l .

This gives us option 2) .
Yes. Good work.
 
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Thank you so much :smile:
 

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