Current Homework Statement & Equations

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SUMMARY

The discussion focuses on calculating electrical parameters for a circuit involving resistors and inductors. Key equations utilized include Ohm's Law (I=V/R), power calculation (P=IV), and the total resistance in a series circuit (R(Total)=sqrt(R(Resistor)^2+R(Inductor)^2)). The calculated values include an inductor resistance of 471.24 ohms, a resistor resistance of 2308.74 ohms, and a total resistance of 2356.12 ohms, leading to a current of 0.65A. The importance of distinguishing between reactance and resistance is emphasized, particularly in the context of AC circuits.

PREREQUISITES
  • Understanding of Ohm's Law (I=V/R)
  • Familiarity with power calculations (P=IV)
  • Knowledge of reactance and impedance in AC circuits
  • Basic concepts of series and parallel circuits
NEXT STEPS
  • Study the calculation of reactance for capacitors and inductors
  • Learn about AC circuit analysis techniques
  • Explore the application of phasors in circuit analysis
  • Investigate the differences between series and parallel circuit calculations
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing AC circuits and their components.

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Homework Statement



Problem-1.jpg


Homework Equations



What is the current entering the node.

The Attempt at a Solution



I=V/R
P=IV -> 510/.470=1085V
R(Inductor)=wL -> 2pi*60*1.25 = 471.24
R(Resistor)=V/I -> 1085/0.47 = 2308.74
R(Total)= sqrt(R(Resistor)^2+R(Inductor)^2) -> 2356.12
V=sqrt(2)*V(RMS) -> 1534.42
I=V/R -> 1534.42/2356.12 = 0.65A
 
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I=V/R
P=IV -> 510/.470=1085V
R(Inductor)=wL -> 2pi*60*1.25 = 471.24 Reactance in OHMS
R(Resistor)=V/I -> 1085/0.47 = 2308.74 OHMS
R(Total)= sqrt(R(Resistor)^2+R(Inductor)^2) -> 2356.12
You can't do this for parallel circuits. You have to work out the currents and then put them in the right angled triangle.

Don't forget that reactance is the term for the impedance of inductors and capacitors, not resistance which is purely for resistors.
 

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