Current in a hollow tube problem

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SUMMARY

The current in a 60.0-cm-long hollow nichrome tube with an inner diameter of 1.10 mm and an outer diameter of 4.20 mm connected to a 3.00 V battery can be calculated using the resistance formula R = ρ * L / A. The resistivity of nichrome is 1.5 x 10-6 ohm meters. The area A is determined by the formula A = π * (outer radius - inner radius)2. After calculating resistance, the current can be found using I = V / R.

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  • Understanding of electrical resistance and Ohm's Law
  • Familiarity with the concept of resistivity
  • Ability to calculate the area of a circular cross-section
  • Knowledge of basic geometry for calculating inner and outer radii
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  • Calculate the resistance of the hollow nichrome tube using R = ρ * L / A
  • Learn how to derive the area A for hollow cylindrical shapes
  • Explore the implications of resistivity in different materials
  • Study the effects of voltage on current in electrical circuits
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1. A 60.0 -cm-long hollow nichrome tube of inner diameter 1.10 mm, outer diameter 4.20 mm is connected to a 3.00 V battery. What is the current in the tube?


Homework Equations


Resistivity for nichrome = 1.5*10^-6 ohm meters
I=V/R
E=V/L


The Attempt at a Solution

 
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I don't know what parts you are having trouble with, but before you can use the equations you posted you have to find the Resistance with the formula R=rho*L/A your A will be pi*(outer radius - inner radius)^2. Then you can proceed.
 

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