1. The problem statement, all variables and given/known data For what electric field strength would the current in a 2.0 mm diameter nichrome wire be the same as the current in a 1.0 mm diameter aluminum wire in which the electric field strength is 0.0080 V/m? aluminum diameter = 1.0 mm Same current(I) flowing through both wires 2. Relevant equations J = sigma*E........ I/A = sigma*E so.....I = sigma*E*A sigma = 1/rho sigma = conductivity; rho = resistivity 3. The attempt at a solution Equating the two currents, I solved for the unknown E-field: E(nichrome) = (E*A*sigma(aluminum))/(A*sigma(nichrome)) rho(nichrome) = 1.1*10^-6 Ωm rho(aluminum) = 2.82*10^-8 Ωm I calculated the E-field to be approximately 0.078 V/m, but this was apparently wrong. Help would be appreciated..!