Current through inductor as function of time

Nick O
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Homework Statement


The L=100 mH inductor in the following figure has an initial current of Io=10 mA. If the voltage is, v(t)=1e−10t+2e−5t V, what is the current, i(t), through the inductor?

Express your answer as a function of time with units of mA.


The figure shows an independent voltage source connected to an inductor.

inductor.PNG

Homework Equations



v = L(di/dt)
i dt = (v dt)/L
[itex]i = \int_{t_0}^{t} v dt + i_0[/itex]

The Attempt at a Solution



I solved the following equation:

[itex]i(t) = \frac{1}{0.1 H}(\int_{t_0}^{t} (e^{-10T}+2e^{-5T}) dT)*\frac{10^3 mA}{1 A} + 10 mA[/itex]

and obtained the following:

[itex]i(t) = (e^{-0.1} + 4e^{-0.05} - e^{-10t} - e^{-5t})*10^3 + 10 mA[/itex]

My homework software rejects this answer, saying that my "answer either contains an incorrect additive numerical constant or is missing one."

I can think of nothing that I might have omitted, and I know that this software is very picky. For example, when rounding, it rejects the "round 5 to even" rule that was instilled in me early on as completely incorrect, always expecting 5 to be rounded up even when followed only by zeroes. Given how picky the software is, I am not altogether convinced that my answer is actually wrong.

Does anyone see any obvious oversights in my work?
 
on Phys.org
Nick O said:

Homework Statement


The L=100 mH inductor in the following figure has an initial current of Io=10 mA. If the voltage is, v(t)=1e−10t+2e−5t V, what is the current, i(t), through the inductor?

Express your answer as a function of time with units of mA.


The figure shows an independent voltage source connected to an inductor.

View attachment 67149

Homework Equations



v = L(di/dt)
i dt = (v dt)/L
[itex]i = \int_{t_0}^{t} v dt + i_0[/itex]

The Attempt at a Solution



I solved the following equation:

[itex]i(t) = \frac{1}{0.1 H}(\int_{t_0}^{t} (e^{-10T}+2e^{-5T}) dT)*\frac{10^3 mA}{1 A} + 10 mA[/itex]

and obtained the following:

[itex]i(t) = (e^{-0.1} + 4e^{-0.05} - e^{-10t} - e^{-5t})*10^3 + 10 mA[/itex]

My homework software rejects this answer, saying that my "answer either contains an incorrect additive numerical constant or is missing one."

I can think of nothing that I might have omitted, and I know that this software is very picky. For example, when rounding, it rejects the "round 5 to even" rule that was instilled in me early on as completely incorrect, always expecting 5 to be rounded up even when followed only by zeroes. Given how picky the software is, I am not altogether convinced that my answer is actually wrong.

Does anyone see any obvious oversights in my work?
What did you use for t0, and why are you not simply using an indefinite integral, then applying the initial condition?
 
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That's a very good question, and tells me that I need to get some sleep. Somehow, my [itex]t_0[/itex] ended up being 0.01 (that is, [itex]i_0[/itex]). What nonsense!

Thanks!
 

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