Find current through inductor after many time constants.

jlmccart03
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Homework Statement


In the figure, R = 1.9 kΩ and ε0 = 60 V . When the switch is closed, the current through the inductor rises to 10 mA in 30 μs .

What will the current in the circuit be after many time constants?

Homework Equations


I = V/R or I = ε/R if current is constant which after many time constants it should be correct?

The Attempt at a Solution


So I attempted to use I = ε/R, but that presented the wrong answer. So then I thought about the question and I remembered that after many time constants that is essentially saying a τ→∞ which would make ε = IR and again I = ε/R so I am not lost on where my thinking was going and if I was even correct in the initial process?
 

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What, precisely, was the value that you calculated and entered?
 
gneill said:
What, precisely, was the value that you calculated and entered?
I got 31.5789 A, which is taking ε = 60V and R = 1.9 Ω. EDIT: The Ω where in kΩ. I just needed to convert it and got the correct answer.
 

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