Currents and magnetic fields in a coil

Click For Summary

Homework Help Overview

The discussion revolves around calculating the magnetic field strength of a horseshoe magnet using given quantities related to a coil, including mass, current, length, and angle. Participants are exploring the relationships between these quantities and the forces acting on the coil.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants are attempting to identify relevant formulas and relationships, such as equating magnetic force to the weight's horizontal component. Some express uncertainty about the adequacy of the provided information and the interpretation of the problem's hints.

Discussion Status

There is an ongoing exploration of the problem, with participants questioning the assumptions and definitions involved, particularly regarding the forces acting on the coil. Some guidance has been offered regarding the need to consider forces and torques in a statics context.

Contextual Notes

Participants note that there are at least three assumptions made in answering the question, and some express concern about the clarity of the problem setup, particularly regarding the horizontal component of weight and the forces keeping the coil in position.

-_-'
Messages
16
Reaction score
0
Please help me if you can...

question: Use the following quantities to calculate the magnetic field strength of the horseshoe magnet.

Mass of coil: 20 grams
current in coil: 2.0 amps
length of bottom of coil: 10cm
angle coil makes with vertical: 30 degrees

Hint: Equate magnetic force on bottom of coil to the horizontal componen of the coils weight.

The question also adds that there are at least 3 assuptions made in answering this question.

I've got a diagram
http://i122.photobucket.com/albums/o272/science_f/0000000000000coilandmagnet.jpg

I don't know where to start in the calculating process:confused: Can someone please help me with the starting point and i'll try and progress from there...this is the first time I've seen a problem like this:blushing:
 
Physics news on Phys.org
these are the formulas I know:
B=F/IL
F=BIL sin @
B=kI/r
B=2(pi)knI

Where k is Amperes constant (2x10^-7NA^-2), L is the length of wire, I is the current, r is the radius of the wire (but in some cases the distance between wires), and F is the force.

Here's another diagram with brainstorming but I'm not sure if i grasp the concept of this...I think it is all wrong:cry:

http://i122.photobucket.com/albums/o272/science_f/000000000000h.jpg

I actually think that there isn't enough information to do the problem unless it is as simple as:
F=mg=20x9.8=196
B=F/IL
B= 196/2.0x10
B=9.8
But i don't think that can be right
 
Last edited:
-_-' said:
Please help me if you can...

question: Use the following quantities to calculate the magnetic field strength of the horseshoe magnet.

Mass of coil: 20 grams
current in coil: 2.0 amps
length of bottom of coil: 10cm
angle coil makes with vertical: 30 degrees

Hint: Equate magnetic force on bottom of coil to the horizontal componen of the coils weight.

The question also adds that there are at least 3 assuptions made in answering this question.

I've got a diagram
http://i122.photobucket.com/albums/o272/science_f/0000000000000coilandmagnet.jpg

I don't know where to start in the calculating process:confused: Can someone please help me with the starting point and i'll try and progress from there...this is the first time I've seen a problem like this:blushing:
What is a horizontal component of weight? I don't think they really mean that. The magnet will exert a force on the lower branch of the coil. You need to think about the direction of the magnetic force. You also need to think about what is keeping the coil in position. There has to be something besides the magnetic force. Something has to be keeping the top of the coil in position. What will be the direction and magnitude of the force on the top of the coil? It will help if you rotate the image so that the magnet is in the plane of the page, and the loop is perpendicular to the page so that the 30 degree tilt can be seen.
 
Last edited:
thanks for that every little bit of info helps
 
-_-' said:
thanks for that every little bit of info helps
Hopefully you will recognize that this becomes a statics problem where one of the forces involved is a magnetic force. Think forces and torques and all the usual things you use for statics problems.
 

Similar threads

Replies
49
Views
6K
  • · Replies 9 ·
Replies
9
Views
4K
Replies
16
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
11
Views
3K
Replies
5
Views
4K
Replies
7
Views
2K