If I understand everything correctly, space near (but outside) a mass is curved negatively, so that if I create a triangle with, for example, rigid rods and the mass in its center, the angles would sum up to less than 180°. (If I am mistaken, please correct me.)(adsbygoogle = window.adsbygoogle || []).push({});

On the other hand, the typical light-bending pictures look like this

I do understand that the space projection of the iight geodesic does not coincide with the shortest path in space as gotten by laying out rods (this is obvious because there is a dt² in the formula for the space-time distance).

But how does the projection of the light geodesics look like, exactly? If I had three stars situated on a triangle with the mass in the middle, would the angular sum of the space projections of the geodesics be smaller or larger than 180°? From the fact that images are shifted away from the central mass, I would think that the sum has to be larger, but I'm not sure.

**Physics Forums - The Fusion of Science and Community**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Curvature of light paths near a mass

Loading...

Similar Threads - Curvature light paths | Date |
---|---|

B GR curvature at light cone surface -- smooth, bent, blocked? | Aug 29, 2017 |

I Question about gravity and speed of light | Jul 18, 2015 |

Does light receive a spacetime curvature upon refraction? | May 7, 2015 |

Light and quantum tunneling | Nov 20, 2014 |

Light bending in the hot plate model of curvature | May 1, 2014 |

**Physics Forums - The Fusion of Science and Community**