Curvature without tidal forces

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Discussion Overview

The discussion revolves around the concept of spacetime curvature in the context of a uniform gravitational field, specifically addressing the absence of tidal forces. Participants explore how spacetime can be considered curved without the presence of non-uniform gravitational effects and the implications of different coordinate systems on the understanding of curvature.

Discussion Character

  • Debate/contested
  • Conceptual clarification
  • Technical explanation

Main Points Raised

  • One participant questions how spacetime can be curved in a uniform gravitational field where tidal forces are absent, noting that clocks at the same height would tick identically.
  • Another participant suggests that in a completely uniform gravitational field, spacetime would be flat, referencing the twin paradox and the independence of curvature from coordinate systems.
  • A repeated inquiry emphasizes the confusion surrounding the introduction of curvature through examples like falling elevators, asking how space can be bent in a uniform gravity scenario.
  • One participant explains that in flat Minkowski spacetime, the curvature tensor is zero, but non-inertial coordinates can lead to non-zero Christoffel symbols, which can create the appearance of curvature without actual curvature being present.
  • Another participant asserts that there is no spacetime curvature in a uniform gravitational field, attributing falling to the observer's non-zero acceleration rather than a gravitational effect, and cautions against relying on non-vanishing Christoffel symbols as a source of confusion.

Areas of Agreement / Disagreement

Participants express differing views on whether spacetime can be considered curved in a uniform gravitational field. Some argue that it cannot, while others suggest that the interpretation of curvature may depend on the chosen coordinate system.

Contextual Notes

The discussion highlights the complexity of interpreting spacetime curvature, particularly in relation to gravitational fields and coordinate systems. There are unresolved assumptions regarding the definitions of curvature and the implications of non-inertial frames.

Ratzinger
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How is spacetime curved if the present gravity field is completely uniform and there are no tidal forces. Clocks at a same height would tick the same, at different heights (to the gravity source) would tick differently. But what about space? How is space curved in the absence of tidal forces?

Often curvature is introduced with falling elevators without tidal forces. The observer in a falling elevator sees a light ray going from on side of the elevator wall to the other as a straight line. An outside observer sees a bended line. Thus gravity bends spacetime they say. Later then tidal forces and the non-uniformity of gravity fields is mentioned and made responsible for curvature.

So again my question: how would space be bent in a complete uniform gravity space?

thank you
 
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In a completely uniform gravitational field, it's my understanding that spacetime would be flat. For example, this page on the twin paradox in flat spacetime mentions that you can understand things from the point of view of the accelerated twin by introducing a uniform gravitational field during the period of acceleration...but the curvature of spacetime is supposed to be independent of your coordinate system, so if the inertial twin sees spacetime as flat throughout the journey, then the accelerating twin should see the same thing.
 
Ratzinger said:
How is spacetime curved if the present gravity field is completely uniform and there are no tidal forces. Clocks at a same height would tick the same, at different heights (to the gravity source) would tick differently. But what about space? How is space curved in the absence of tidal forces?

Often curvature is introduced with falling elevators without tidal forces. The observer in a falling elevator sees a light ray going from on side of the elevator wall to the other as a straight line. An outside observer sees a bended line. Thus gravity bends spacetime they say. Later then tidal forces and the non-uniformity of gravity fields is mentioned and made responsible for curvature.

So again my question: how would space be bent in a complete uniform gravity space?

thank you

If you have a flat Minkowski space-time, the curvature tensor is zero, and this will be true regardles of the coordinate system used.

However, if you adopt non-inertial coordinates to describe a flat minkowskian space-time, like the coordinate system of an accelerated observer, you can make the Chirsotffel symbols non-zero, even though you can never make the curvature tensor non-zero.

Non-zero Christoffel symbols can cause, for instance, the opposite sides of a parallelogram to have different lengths. This is somtimes called "curvature", but that's really speaking very losely. It's quite commonly done, though, including in many textbooks.
 
Ratzinger said:
How is spacetime curved if the present gravity field is completely uniform and there are no tidal forces. Clocks at a same height would tick the same, at different heights (to the gravity source) would tick differently. But what about space? How is space curved in the absence of tidal forces?

Often curvature is introduced with falling elevators without tidal forces. The observer in a falling elevator sees a light ray going from on side of the elevator wall to the other as a straight line. An outside observer sees a bended line. Thus gravity bends spacetime they say. Later then tidal forces and the non-uniformity of gravity fields is mentioned and made responsible for curvature.

So again my question: how would space be bent in a complete uniform gravity space?

thank you
At one time (before I learned GR) I wondered about this too so after I learned GR I wrote up the answers to your question in this article

http://xxx.lanl.gov/abs/physics/0204044

Pete
 
As already mentioned, there is no spacetime curvature with a uniform gravitational field. The modern interpretation is that things "fall" in such fields due to the observer's nonzero (4-)acceleration (the magnitude of which is an invariant), and that it really isn't a gravitational effect.

Of course other interpretations are possible - and are occasionally convenient - but this one tends to be the most foolproof. Relying on nonvanishing Christoffel symbols is a great way to confuse yourself. Even the physicists working on GR were confused by it (and similar ideas) back when such statements were still popular. Hardly anyone made any progress in the field until the old coordinate-dependent notions were removed from everyones' minds. That took about 40 years.
 

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