Curvilinear (n/t) motion (find magnitude of acceleration)

  • Thread starter smruthi92
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  • #1
15
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pls see the attachment. so pretty much magnitude of acc would be root (at2 + an2). i figured out an by subbing it into v2/p. but i cant figure out how to calculate at!

id really appreciate the help, ive been at it for 3 hours now!!!!!! thanks!
 

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Answers and Replies

  • #2
15
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ok lemme show my working:

normal acc = 0.009^2/0.066

tangential acc i tried this:

s=r theta
s = 0.066 times (66/180)*pie
s = 0.07603
v = d/t
t = d/v
t = 0.07603/0.009
t= 8.4477 seconds

therefore acc = v/t
acc = 0.09/8.4477

then i squared this and the normal acc, but its not the right answer
 

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