Curvilinear (n/t) motion (find magnitude of acceleration)

[smruthi92]

pls see the attachment. so pretty much magnitude of acc would be root (a_t² + a_n²). i figured out a_n by subbing it into v²/p. but i can't figure out how to calculate a_t!

id really appreciate the help, I've been at it for 3 hours now! thanks!

 

[smruthi92]

ok let me show my working:

normal acc = 0.009^2/0.066

tangential acc i tried this:

s=r theta
s = 0.066 times (66/180)*pie
s = 0.07603
v = d/t
t = d/v
t = 0.07603/0.009
t= 8.4477 seconds

therefore acc = v/t
acc = 0.09/8.4477

then i squared this and the normal acc, but its not the right answer