Curvilinear (n/t) motion (find magnitude of acceleration)

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SUMMARY

The discussion focuses on calculating the magnitude of acceleration in curvilinear motion using the formula for total acceleration, which is the square root of the sum of the squares of tangential and normal accelerations. The user successfully calculated the normal acceleration as 0.00135 m/s² but struggled with the tangential acceleration. They attempted to derive tangential acceleration using the relationship between distance, velocity, and time, ultimately arriving at an incorrect value. The correct approach involves accurately determining the tangential acceleration from the provided parameters.

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smruthi92
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pls see the attachment. so pretty much magnitude of acc would be root (at2 + an2). i figured out an by subbing it into v2/p. but i can't figure out how to calculate at!

id really appreciate the help, I've been at it for 3 hours now! thanks!
 

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ok let me show my working:

normal acc = 0.009^2/0.066

tangential acc i tried this:

s=r theta
s = 0.066 times (66/180)*pie
s = 0.07603
v = d/t
t = d/v
t = 0.07603/0.009
t= 8.4477 seconds

therefore acc = v/t
acc = 0.09/8.4477

then i squared this and the normal acc, but its not the right answer
 

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