Cylindrical and Spherical Coordinates Changing

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SUMMARY

This discussion focuses on converting coordinates from spherical to cylindrical and Cartesian systems, specifically using the values r = 3, θ = -π/6, and φ = -1. The correct conversions yield cylindrical coordinates of (2.52, -π/6, 1.62) and Cartesian coordinates of (-2.18, -1.26, 1.62). The conversation highlights the importance of understanding the conventions used for spherical coordinates, particularly the interpretation of negative values for r and φ, which involve reflections through the origin and adjustments in angle.

PREREQUISITES
  • Understanding of spherical coordinates and their components (r, θ, φ).
  • Knowledge of cylindrical coordinates and their conversion formulas.
  • Familiarity with Cartesian coordinates and their relationship to polar coordinates.
  • Basic trigonometry and geometry principles related to coordinate transformations.
NEXT STEPS
  • Study the conversion formulas between spherical and cylindrical coordinates.
  • Learn about the geometric interpretation of negative values in polar and spherical coordinates.
  • Explore the mathematical implications of coordinate reflections in three-dimensional space.
  • Investigate the differences in conventions for angles used in mathematics and physics.
USEFUL FOR

Students and educators in mathematics, physics, and engineering who are dealing with coordinate transformations and need clarity on spherical and cylindrical coordinate systems.

theBEAST
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Homework Statement


Convert the following as indicated:

1. r = 3, θ = -π/6, φ = -1 to cylindrical

2. r = 3, θ = -π/6, φ = -1 to cartesian

The Attempt at a Solution


I just want to check if my answers are correct.

1. (2.52, -π/6, 1.62)
2. (-2.18, -1.26, 1.62)
 
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theBEAST said:

Homework Statement


Convert the following as indicated:

1. r = 3, θ = -π/6, φ = -1 to cylindrical

2. r = 3, θ = -π/6, φ = -1 to cartesian

The Attempt at a Solution


I just want to check if my answers are correct.

1. (2.52, -π/6, 1.62)
2. (-2.18, -1.26, 1.62)

What coordinate system are these given in? ##r## is usually used in cylindrical coordinates and ##\rho## for spherical. Also, if ##\phi## is the spherical coordinate angle from the ##z## axis, it is usually restricted to the interval ##[0,\pi]##. Are you sure you copied the ##\phi## values correctly?
 
Mathematicians and physicists use ##\theta## and ##\phi## differently. You need to tell us which convention you're using here.
 
Here is the question with the answer key:
cIwN3.png


In this case r = ρ and I'm not sure why phi is negative.

I don't think the answer key is correct.
 
The answer key is correct. You need to show us your calculations. To answer #1, it's probably most straightforward if you do #2 first and the convert from Cartesian to cylindrical.
 
vela said:
The answer key is correct. You need to show us your calculations. To answer #1, it's probably most straightforward if you do #2 first and the convert from Cartesian to cylindrical.

For number one, how can r be negative? They have -2.52 whereas I have 2.52. It is why I thought the answer key was wrong.
 
When r is negative, you reflect through the origin from where you'd otherwise be. In polar coordinates, for instance, the point r=-1, θ=π/4 would correspond to (-1/√2, -1/√2), which is where you'd end up if you reflected r=1, θ=π/4 through (0,0).

You'll notice they gave you a second answer where r is positive, but the angle has been changed to account for the reflection.
 
vela said:
When r is negative, you reflect through the origin from where you'd otherwise be. In polar coordinates, for instance, the point r=-1, θ=π/4 would correspond to (-1/√2, -1/√2), which is where you'd end up if you reflected r=1, θ=π/4 through (0,0).

You'll notice they gave you a second answer where r is positive, but the angle has been changed to account for the reflection.

Lastly, when ρ is negative does that mean the angle starts from the -z axis? Because when ρ is positive it starts from the positive z axis.
 
Not exactly. Reflection in spherical coordinates takes ##\phi \to \pi-\phi## and ##\theta \to \theta+\pi##. The change to ##\phi## effectively means you're measuring from the -z-axis, but you also have to accompany it with a rotation by 180 degrees about the z-axis.
 

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